In right triangle ABC, AB=6, BC=12, and m∠A=90°. What is the value of cot C?

A company has six employees.The salary of five of the employees are P2200,P1300,P800,P940 and P560.When the sixth employee is in

Dafna1 [17]

Answer:

First answer is 1200

Second answer is 900 for each new employee

Step-by-step explanation:

First answer:

2200+1300+800+940+560+x = 7000

5800+x = 7000 subtract 5800 from both sides and you get your answer

x = 1200

Second answer:

x = 900. Each of the two employees made 900 a month or 1800 a month for both of them.

To find the average we take the total salaries and divide by the number of people to find the average salary. In this case, we know the average and we know all of the salaries, but two. We can figure this out.

(7000 + 2x)/8 = 1100 multiple both sides by 8 to clear the fraction/

7000 +2x = 8800 Subtract both sides by 7000

2x = 1800 Divide both sides by 2

x = 900

3 0

1 year ago

Can you just give me answers

sammy [17]

Answer:

to what

Step-by-step explanation:

5 0

3 years ago

A Norman window is a window with a semi-circle on top of regular rectangular window. (See the picture.) What should be the dimen

Vikki [24]

Answer:

bottom side (a) = 3.36 ft

lateral side (b) = 4.68 ft

Step-by-step explanation:

We have to maximize the area of the window, subject to a constraint in the perimeter of the window.

If we defined a as the bottom side, and b as the lateral side, we have the area defined as:

$A=A_r+A_c/2=a\cdot b+\dfrac{\pi r^2}{2}=ab+\dfrac{\pi}{2}\left (\dfrac{a}{2}\right)^2=ab+\dfrac{\pi a^2}{8}$

The restriction is that the perimeter have to be 12 ft at most:

$P=(a+2b)+\dfrac{\pi a}{2}=2b+a+(\dfrac{\pi}{2}) a=2b+(1+\dfrac{\pi}{2})a=12$

We can express b in function of a as:

$2b+(1+\dfrac{\pi}{2})a=12\\\\\\2b=12-(1+\dfrac{\pi}{2})a\\\\\\b=6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a$

Then, the area become:

$A=ab+\dfrac{\pi a^2}{8}=a(6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a)+\dfrac{\pi a^2}{8}\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a^2+\dfrac{\pi a^2}{8}\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{4}-\dfrac{\pi}{8}\right)a^2\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{8}\right)a^2$