If you would like to know how much dip remains, you can calculate this using the following steps:
1 quart = 32 ounces
<span>1 quart and 2 ounces = 32 ounces + 2 ounces = 34 ounces of vegetable dip
</span>1 cup = 8 ounces<span>3 cups = 3 * 8 ounces = 24 ounces
</span><span>3 cups and 3 ounces = 24 ounces + 3 ounces = 27 ounces poured into a bowl
</span>
remaining: 34 ounces - 27 ounces = 7 ounces
The correct result would be 7 ounces.
Answer:
Second option is the right choice.
Step-by-step explanation:
<span>R={(r;s) | r,s ε (-∞,∞) : r=s/10}</span>
Answer: P(x > - 0.23) = 0.41
Step-by-step explanation:
Since we are assuming that the readings at freezing on a batch of thermometers are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = the readings at freezing on a batch of thermometers.
µ = mean temperature reading
σ = standard deviation
From the information given,
µ = 0°C
σ = 1.00°C
the probability of obtaining a reading less than -0.23°C is expressed as
P(x > - 0.23)
For x = - 0.23
z = (- 0.23 - 0)/1 = - 0.23
Looking at the normal distribution table, the probability corresponding to the z score is 0.41
0.50 m *100 Hz
= 50m/s I really hope this helps!
