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topjm [15]
3 years ago
10

Your new phew is standing on his deck which is 4 feet off the ground. He tosses his toy up into the air. The equation h(t) = -2t

^2 + 7t +4 models the toys height, h, from the ground at t seconds after he threw it. How high is the toy after 1 second
Mathematics
1 answer:
Tpy6a [65]3 years ago
3 0

Answer:

The height of the toy is 9 feet after 1 second

Step-by-step explanation:

we have

h(t)=-2t^2+7t+4

where

h(t) is the toys height from the ground

t is the time in seconds

so

For t=1 sec

substitute the value of t in the quadratic equation and solve for h(t)

h(1)=-2(1)^2+7(1)+4

h(1)=9\ ft

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Answer:

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Step-by-step explanation:

Please find the attachment.

Let x represent the distance between KA-7 and KA-11.

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We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.  

(AB)^2=(AC)^2+(BC)^2-2(AC)(BC)*cos (C)

Upon substituting our given values in above formula we will get,

x^2=1200^2+1700^2-2*1200*1700*cos (52^o)  

x^2=1440000+2890000-4080000*0.615661475

x^2=4330000-2511898.81933008

x^2=1818101.18066992

Let us take square root of both sides of our equation.

x=\sqrt{1818101.18066992}

x=1348.3698234\approx 1348

Therefore, KA-7 and KA-11 are approximately 1348 light years apart.

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