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kkurt [141]
3 years ago
5

A 25kg steel block rests on a horizontal steel surface. Calculate the maximum horizontal force P, that can be applied onto the b

lock without the block sliding across the surface.
Physics
1 answer:
SVEN [57.7K]3 years ago
8 0
To calculate that, we'd need to know the coefficient of static friction between the block and the surface, which you haven't told us.
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A 0.40-kg mass, attached to the end of a 0.75-m string, is whirled around in a circular horizontal path. If the maximum tension
hichkok12 [17]

To solve this problem we will apply the concepts given from the circular movement of the bodies for which we have that the centripetal Force is defined as a product between the mass and the velocity squared at the rate of rotation, mathematically this is

F_c = \frac{mv^2}{r}

Where,

m = Mass

v = Velocity

r = Radius

Our values are given as

m = 0.4kg\\r = 0.75m\\F_c = 450N

Rearranging to find the velocity we have that,

F_c = \frac{mv^2}{r}

v = \sqrt{\frac{F_c * r}{m}}

v = \sqrt{\frac{450 * 0.75}{0.4}}

v = 29.0474m/s

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Flow around curved height contours requires the incorporation of the centrifugal force. What is the general term to describe the
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(1 point) A mass m=4kg is attached to both a spring with spring constant k=577N/m and a dash-pot with damping constant c=4N⋅s/m
sasho [114]

Answer:

The function is x = e^(-t/2) * (0.792*sin12t + 5cos12t)

Explanation:

we have to:

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c = damping constant = 4 N*s/m

The differential equation of motion is equal to:

m(d^2x/dt^2) + c(dx/dt) + k*x = 0

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4(d^2x/dt^2) + 4(dx/dt) + 577*x = 0

Thus, we have:

4*x^2 + 4*x + 577 = 0

we will use the quadratic equation to solve the expression:

x = (-4 ± (4^2 - (4*4*577))^1/2)/(2*4) = (-4 ± (-9216))/8 = (1/2)  ± 12i

The solution is equal to:

x = e^(1/2) * (c1*sin12t + c2*cos12t)

x´ = (-1/2)*e^(1/2) * (c1*sin12t + c2*cos12t) + e^(-t/2) * (12*c1*cos12t - 12*c2*sin12t)

We have the follow:

x(0) = 5

e^0(0*c1 + c2) = 5

c2 = 5

x´(0) = 7

(-1/2)*e^0 * (0*c1 + c2) + e^0 * (12*c1 - 0*c2) = 7

(-1/2)*(5) + 12*c1 = 7

Clearing c1:

c1 = 0.792

The function is equal to:

x = e^(-t/2) * (0.792*sin12t + 5cos12t)

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Answer:

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