Answer:
A contact force requires two objects to be touching, a field force works at a distance
Explanation:
- A contact force is a force that requires the two objects to be touching. An example of contact force is the frictional force: in fact, frictional force only occurs if the surfaces of the two objects involved touch each other, otherwise it is not present.
- A field force is a force that acts on a distance, i.e. the objects involved do not need to touch. Examples of field force are the gravitational force and the electric force: in fact, an object with mass 
experiences a force of gravity when it is near a planet, but this force is present also when the object is not touching the planet. Similarly, electric charges experience an electric force when they are close to other electri charges, even when they are separated by a certain distance r. For this non-contact forces, we use the concept of field to identify the region of space in which an object experiences that force.
Answer:
the planet Uranus has mass 8.7 x 1025 kg. ... radius 5.1 x 107 m around Uranus. G= 6.7 x ... The gravitational potential of the satellite is its centripetal force. ... Moon. Use this idea to calculate the mass of the Earth M from the values of vand rgiven ... 9mm . Ve GM. Ma var. 1023** 3-8* 10". M= ... 5.9x1024... kg [2]. 6-7x 10-11.
Answer:
μ= 0.408 : coefficient of kinetic friction
Explanation:
Kinematic equation for the box:
Formula( 1)
a= acceleration
v_i= initial speed =0
v_f= final speed= 20 m/s
t= time= 5 s
We replace data in the formula (1):
a= - 4m/s²
Box kinetics: We apply Newton's laws in x-y:
∑Fx=ma : second law of Newton
-Ff= ma Equation (1)
Ff is the friction force
Ff=μ*N Equation (2)
μ is the coefficient of kinetic friction
N is the normal force
Normal force calculation
∑Fy=0 : Newton's first law
N-W=0 W is the weight of the box
N=W= m*g : m is the mass of the box and g is the acceleration due to gravity
N=9.8*m
We replace N=9.8m in the equation (2)
Ff=μ*9.8*m
Coefficient of kinetic friction ( μ) calculation
We replace Ff=μ*9.8*m and a= -4m/s² in the equation (1):
-μ*9.8*m: -m*4 : We divide by -m on both sides of the equation
9.8*μ=4
μ=4 ÷ 9.8
μ= 0.408
Answer:
the current will improve in performance and tell me if im correct
Gene–environment interaction (or genotype–environment interaction or G×E) is when two different genotypes respond to environmental variation in different ways. A norm of reaction is a graph that shows the relationship between genes and environmental factors when phenotypic differences are continuous.
