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SVEN [57.7K]
3 years ago
10

The soon to be released skylake chipset architecture will use what socket?

Physics
1 answer:
Flauer [41]3 years ago
7 0
The answer is LGA1151.  <span>The soon to be released skylake chipset architecture will use LGA1151  socket A</span><span>lso known as </span>Socket H4<span>, it is an </span>Intel  microprocessor<span> compatible </span>socket<span> which comes in two distinct versions: the first revision which supports both Intel's </span>Skylake[2]<span> and </span>Kaby Lake<span> CPUs, and the second revision which supports </span>Coffee Lake<span> CPUs exclusively.</span>
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Consider two point charges located on the x axis: one charge, q1= -11.0 nC, is located at x1= -1.675 m; the second charge, q2= 3
Mekhanik [1.2K]

Answer:

Please refer to the figure.

q1 is a negative charge, and q2 and q3 are positive charges. So, the force exerted by q1 on q3 is attractive, and the force exerted by q2 on q3 is repulsive, which means F13 is directed towards left, and F23 is also directed towards left.

F_{13} = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_3}{r_1^2} = \frac{1}{4\pi \epsilon_0}\frac{11\times 10^{-9}\times 47.5\times10^{-9}}{(-1.675 - (-1.18))^2} = 1.92\times 10^{-5}N

F_{23} = \frac{1}{4\pi\epsilon_0}\frac{q_2q_3}{r_2^2} = \frac{1}{4\pi\epsilon_0}\frac{31\times 10^{-9} \times 47.5\times 10^{-9}}{(-1.18 - 0)^2} = 9.5\times 10^{-6}

The net force on q3 is the sum of these two forces:

F_{net} = F_{13} + F_{23} = -1.92\times 10^{-5} + (-19.5\times10^{-6}) = 2.8\times 10^{-5} N

Since both forces are directed towards left, their sign should be negative.

5 0
3 years ago
At Alpha Centauri's surface, the gravitational force between Alpha Centauri and a 2 kg mass of hot gas has a magnitude of 618.2
sergeinik [125]

Answer:

6.86 * 10^8 m

Explanation:

Parameters given:

Mass of hot gas, m = 2 kg

Gravitational Force, F = 618.2 N

Mass of Alpha Centauri, M = 2.178 * 10^30 kg

The gravitational force between two masses (the hot gas and Alpha Centauri) , m and M, at a distance, r, given as:

F = (G*M*m) / r²

Where G = gravitational constant

Therefore,

618.2 = (6.67 * 10^(-11) * 2.178 * 10^30 * 2) / r²

=> r² = (6.67 * 10^(-11) * 2.178 * 10^30 * 2) / 618.2

r² = 4.699 * 10^17 m²

=> r = 6.86 * 10^8 m

We are told that the hot gas is on the surface of Alpha Centauri, hence, the distance between both their centers is the radius of Alpha Centauri.

The mean radius of Alpha Centauri is 6.86 * 10^8 m.

5 0
3 years ago
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Moira is experiencing noticeable memory loss, muscle loss, and bone loss. What age group is Moira most likely in?
nlexa [21]
Late adulthood is the answer
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3 years ago
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PLS HELP MEE ill literally suck you off JUST PLS and mark you brainliest
Svetlanka [38]
Do i have to answer the question and still have the offer on the table
7 0
3 years ago
Krystal is exploring the properties of iron. She takes a large iron nail and finds that the nail does not attract other metal ob
RideAnS [48]

Explanation:

Iron has tiny magnetic domains inside it. Each domain acts like a tiny magnet with its own magnetic field. These domains are randomly distributed thus resulting in zero magnetic field and iron doesn't behave like a magnet.

When a copper wire is wound around the nail and current is passed through the coil, magnetic field is generated. This magnetic field penetrates through the nail. Due to this the magnetic domains of the nail align in the same direction thus having a net magnetic field. The nail behaves like a magnet till the time current flows through the coil.

4 0
3 years ago
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