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Gekata [30.6K]
4 years ago
14

A stack of books rests on a level frictionless surface. A force F acts on the stack, and it accelerates at 3.0 m/s2. A 1.0 kg bo

ok is then added to the stack. The same force is applied, and now the stack accelerates at 2.0 m/s2.
Physics
1 answer:
Oxana [17]4 years ago
4 0

Answer:

m1 = 2 kg

m2 = 3kg

Explanation:

The force can be getting by

F = m * a

F1 = F2

a1 = 3.0 m/s^2

a2 = 2.0 m/s^2

The force F1=F2 because the force is applied so get the a2 acceleration

m1 * a1 = m2 * a2

m2 = m1 + 1kg

m1 *(3.0 m/s^2) = m2* (2.0 m/s^2)

m1 *(3.0 m/s^2) = (m1 + 1kg) * (2.0 m/s^2)

m1*(3.0m/s^2-2.0m/s^2)=2 kg*m/s^2

Solve to find the mass

m1 m/s^2= 2 kg*m/s^2

m1 = 2 kg

m2 = 3kg

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Answer:

The final temperature of the gas is <em>114.53°C</em>.

Explanation:

Firstly, we calculate the change in internal energy, ΔU from the first law of thermodynamics:

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Secondly, from the ideal gas law, we calculate the final temperature of the gas, using the change in internal energy:

ΔU=\frac{3}{2} nRΔT

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Then we make the final temperature, T₂, subject of the formula:

T_{2} =\frac{2ΔU}{3nR} +T_{1}

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T_{2} =114.53 deg.C

Therefore the final temperature of the gas, T₂, is 114.53°C.

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From the information given above, 
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