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3 years ago

100 points! please help!!!

Physics

2 answers:

sergejj [24]3 years ago

8 0

Answer:

Explanation:

ur pic shows the net velocity of plane

315deg from east means the inside angle of the triangle is 45deg

eastbound distance traveled is 30xcos45deg.x2 = 42.4264km

northboud distance traveled is (100-30xcos45deg.)x2 = 157.5736km

IRINA_888 [86]3 years ago

7 0

Answer:

Explanation:

A plane flies due north (90° from east) with a velocity of 100 km/h for 2 hours.

With no wind, it will be 100*2 = 200 km north of its starting point.

But a steady wind blows southeast at 30 km/h at an angle of 315° from due east.

So the wind itself will blow the plane 30*2 = 60km at an angle of 315° from due east.

That is the same as 60*cos315° = 42.43km due east and 60*sin315° = -42.43km north.

Combining, the plane is at 42.43km due east and 200-42.43 = 157.57km due north from its starting point.

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tigry1 [53]

Answer:

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Put the value into the formula

$E=\dfrac{1}{2}\times38\times10^{-3}\times(0.01925)^2$

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{tex]E=7.04\ \mu J[/tex]

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Answer:

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Therefore;

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Explanation:

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