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Mandarinka [93]
3 years ago
12

100 points! please help!!!

Physics
2 answers:
sergejj [24]3 years ago
8 0

Answer:

Explanation:

ur pic shows the net velocity of plane

315deg from east means the inside angle of the triangle is 45deg

eastbound distance traveled is 30xcos45deg.x2 = 42.4264km

northboud distance traveled is (100-30xcos45deg.)x2 = 157.5736km

IRINA_888 [86]3 years ago
7 0

Answer:

Explanation:

A plane flies due north (90° from east) with a velocity of 100 km/h for 2 hours.

With no wind, it will be 100*2 = 200 km north of its starting point.

But a steady wind blows southeast at 30 km/h at an angle of 315° from due east.

So the wind itself will blow the plane 30*2 = 60km at an angle of 315° from due east.

That is the same as 60*cos315° = 42.43km due east and 60*sin315° = -42.43km north.

Combining, the plane is at 42.43km due east and 200-42.43 = 157.57km due north from its starting point.

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On substituting the value of "A", we get

⇒  \frac{F_2}{F_1} =\frac{\pi r_2^2}{\pi r_1^2}

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