Answer:
m < EAD = 29 degrees
m < CAB = 119 degrees
Given :
The question states that m < CAE = m<FAB = 61 degrees and m<DAF = 90 degrees
Solution:
1. Since line CAF and EAB intersect each other, m<CAF = m< EAF - (opposite vertical angles are equivalent)
2. m<BAC + m<EAC = 180 degrees (sum of linear pair)
3. m<CAB = 180 degrees - m<EAC
4. Equation 1: m<CAB = m<EAF = 119 degrees
5. m<EAF = m<EAD + m< DAF
6. m<EAD = m<EAF - m<DAF
7. m<EAD = 119 degrees-90 degrees = 29 degrees
Hope this helps!!! :)
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Answer:
13
Step-by-step explanation:
Since OCB forms a right triangle, you can find the length of side OB and therefore the radius by simply using the pythagorean theorem. The first step is to note that, since AB=24 and OC bisects that, that both CB and AC have length 12. Therefore, the radius is
. Hope this helps!
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Answer:
25% off $80.00 is <u><em>$60.00 </em></u>
The difference is $20.00
Step-by-step explanation:
Hope this Helps!!!
Answer:
![\log_5{\dfrac{x^5}{\sqrt[4]{8-x}}}](https://tex.z-dn.net/?f=%5Clog_5%7B%5Cdfrac%7Bx%5E5%7D%7B%5Csqrt%5B4%5D%7B8-x%7D%7D%7D)
Step-by-step explanation:
Make use of the rules of logarithms:
log(a/b) = log(a) - log(b)
log(a^b) = b·log(a)
__
![5\log_5{x}-\dfrac{1}{4}\log_5{(8-x)}=\log_5{x^5}-\log_5{\sqrt[4]{8-x}}=\log_5{\dfrac{x^5}{\sqrt[4]{8-x}}}](https://tex.z-dn.net/?f=5%5Clog_5%7Bx%7D-%5Cdfrac%7B1%7D%7B4%7D%5Clog_5%7B%288-x%29%7D%3D%5Clog_5%7Bx%5E5%7D-%5Clog_5%7B%5Csqrt%5B4%5D%7B8-x%7D%7D%3D%5Clog_5%7B%5Cdfrac%7Bx%5E5%7D%7B%5Csqrt%5B4%5D%7B8-x%7D%7D%7D)