Answer:
The circumference of the circle is 6 cm (approximately).
Step-by-step explanation:
Given:
Area of the circle = 1/4π²
Now, to get the circumference of the circle we need the radius.
So, finding the radius by putting the formula of area:
Area = ![\pi r^{2}](https://tex.z-dn.net/?f=%20%5Cpi%20r%5E%7B2%7D)
=
dividing π by both sides:
![\frac{1}{4}\pi](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%5Cpi)
![=r^{2}](https://tex.z-dn.net/?f=%3Dr%5E%7B2%7D)
using square root on both the sides:
![\frac{1}{2}\sqrt{\pi } = r](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Csqrt%7B%5Cpi%20%7D%20%3D%20r)
So, the radius is ![\frac{1}{2}\sqrt{\pi }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Csqrt%7B%5Cpi%20%7D%20)
Now, putting the formula of circumference:
![circumference=2\pi r](https://tex.z-dn.net/?f=circumference%3D2%5Cpi%20r)
=![2\pi\frac{1}{2} \sqrt{\pi}](https://tex.z-dn.net/?f=2%5Cpi%5Cfrac%7B1%7D%7B2%7D%20%5Csqrt%7B%5Cpi%7D)
=![\pi \sqrt{\pi}](https://tex.z-dn.net/?f=%5Cpi%20%5Csqrt%7B%5Cpi%7D)
putting the value of π =3.14
=![3.14\times\sqrt{3.14}](https://tex.z-dn.net/?f=3.14%5Ctimes%5Csqrt%7B3.14%7D)
=![3.14\times1.77](https://tex.z-dn.net/?f=3.14%5Ctimes1.77)
=![5.56](https://tex.z-dn.net/?f=5.56)
Circumference = 5.56 cm
Therefore, the circumference of the circle is 6 cm (approximately).
Answer:
The total surface area of this cuboid is 132.5 sq.cm
Answer:
Step-by-step explanation:
Request of activities so increase then division, at that point deduction and expansion.
9*8 = 72
72/2 = 36
72-3 = 69
69+36 = 105
Another way of saying it is:
Utilize the request for tasks to improve on mathematical articulations. The request is brackets, types and roots, augmentation and division, expansion and deduction. Duplication and division are "something similar" so you would utilize the first that happens from left to right.
Bit by bit clarification:
7^2 - 3 + 9 x 8 ÷ 2
49 - 3 + 9 x 8 ÷ 2
49 - 3 + 72 ÷ 2
49 - 3 + 36
49 - 39
W=10
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