The average rate of change of a function f(x) in an interval, a < x < b is given by
Given q(x) = (x + 3)^2
1.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -4 is given by
2.) The average rate of change of q(x) in the interval -3 ≤ x ≤ 0 is given by
3.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -3 is given by
4.) The average rate of change of q(x) in the interval -3 ≤ x ≤ -2 is given by
5.) The average rate of change of q(x) in the interval -4 ≤ x ≤ -3 is given by
6.) The average rate of change of q(x) in the interval -6 ≤ x ≤ 0 is given by
Answer:
ok.
what benchmark 1 1/8 is closet to (ps benchmarks on the side) and do the same for 2 2/5 . and the benchmarks that you found subtract them.
lol sorry though I don't know sorry
Step-by-step explanation:
Answer:
Function 1 has a greater Y intercept than that of function 2
Step-by-step explanation:
Y intercept can be found by replacing x by 0 or
x = 0 0f the given function.
in this case Function 1 has a Y intercept of 5 when x =0
on the other hand, function 2 crosses the y axis once at -1 which is the y intercept.
you can now clearly see that
y = 5 > y = -1
---> 5>-1
so that's why we conclude that 1 has a greater Y intercept.
Answer:
0.613 ...............................