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2 years ago

a city has a population of 45,000. Its decreasing by 2% per year. what will population be after 15 years

Mathematics

1 answer:

Gnom [1K]2 years ago

8 0

It will be about 32,571 people

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Find the area of the shaded sector of the circle. Use pi=3.14

Neporo4naja [7]

Answer:

If radius of circle = 1, the shaded sector area is calculated by:

A = pi x radius^2 x (136 x 2)/360 = 3.14 x 1^2 x 272/360 =2.37

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3 years ago

The fraction 4/5 is equivalent to 0.8 and 80%. How do I write 0.8 and 80% as unreduced fractions?

kolezko [41]

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

Hello!

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❖ You can write 0.8 as 8/10 and 80% as 80/100.

(8/10 and 8/100 are equivalent.)

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2 years ago

Can someone help me with my algebra class?

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2 years ago

Who is correct? Thanks for the help

Aleksandr-060686 [28]

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2 years ago

Line segment NY has endpoints N(-11, 5) and Y(3,-3).

777dan777 [17]

Given:

Line segment NY has endpoints N(-11, 5) and Y(3,-3).

To find:

The equation of the perpendicular bisector of NY.

Solution:

Midpoint point of NY is

$Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

$Midpoint=\left(\dfrac{-11+3}{2},\dfrac{5-3}{2}\right)$

$Midpoint=\left(\dfrac{-8}{2},\dfrac{2}{2}\right)$

$Midpoint=\left(-4,1\right)$

Slope of lines NY is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

$m=\dfrac{-3-5}{3-(-11)}$

$m=\dfrac{-8}{14}$

$m=\dfrac{-4}{7}$

Product of slopes of two perpendicular lines is -1. So,

$m_1\times \dfrac{-4}{7}=-1$

$m_1=\dfrac{7}{4}$

The perpendicular bisector of NY passes through (-4,1) with slope $\dfrac{7}{4}$ . So, the equation of perpendicular bisector of NY is

$y-y_1=m_1(x-x_1)$

$y-1=\dfrac{7}{4}(x-(-4))$

$y-1=\dfrac{7}{4}(x+4)$

$y-1=\dfrac{7}{4}x+7$

Add 1 on both sides.

$y=\dfrac{7}{4}x+8$

Therefore, the equation of perpendicular bisector of NY is $y=\dfrac{7}{4}x+8$ .

6 0

2 years ago