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ziro4ka [17]
2 years ago
14

How canyou determine if two ratios are equivalent

Mathematics
1 answer:
umka2103 [35]2 years ago
8 0
By multiplying each ratio by the second number of the other ratio, you can determine if they are equivalent. Multiply both numbers in the first ratio by the second number of the second ratio. For example, if the ratios are 3:5 and 9:15, multiply 3 by 15 and 5 by 15 to get 45:75.
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Simplify. (x6 y3)(−8xy2)(−6x3)
meriva
When simplifying this, we would have to take this little by little in serious steps and not only this, but to also take notice of the use of <u>pemdas</u> and to make sure that we take each step carefully.

We first would <u></u><u>(first)</u> simplify the following:

(((x^6)*(y^3))*(0-(8x*(y^2))))*(0-(2*3x^3)) \\ \\ then \ we \ would \ do . .  . . \\ \\  x^7  \ multiplied \ by \ x^3 \ = x^(^7^ +^ 3^) = \ x^1^0 \\ \\ (last \ step).... \\ \\ 2^3 \   multiplied \ by \ 2^1   = 2^(^3^ +^ 1^) = 2^4 \\ \\ \Longrightarrow \ (your \ answer) \\ \\ \boxed{\bf{  (2^4*3x^1^0y^5)}}
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3 years ago
Graph y= x−2.<br> PLZZ HELP
nataly862011 [7]

Explanation: To graph the equation y = x - 2, the idea is simple.

We pick three values for <em>x</em>, plug them into the

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In order to do this in an organized way, we set up a chart.

Down the left side we make a column for our x's, down the right side we make a column for our y's, and in the middle we make a column for the side of the equation that contains the <em>x</em>, in this case, x - 2.

So reading the chart from left to right, we have our <em>x</em> or what we plug into the equation, then we have the x - 2 or what happens to the x when we plug it into the equation, and finally we have our <em>y</em> or what we end up with after plugging <em>x</em> into the equation.

So our first step in filling out the chart is choosing

the x's that we want to plug into the equation.

When graphing lines, I always choose three x's,

a positive number, zero, and a negative number.

The easiest numbers to pick are usually 1, 0, and -1.

So for 1, we plug a 1 into the equation for <em>x</em>

and we have y = (1) - 2 or -1

For 0 we plug a 0 into the equation for <em>x</em>

and we have y = (0) - 2 or -2.

For -1 we plug a -1 into the equation for <em>x</em>

and we have y = (-1) - 2 or -3.

So our points are (1, -1), (0, -2), and (-1, -3).

I looked at the x and y column to find those points.

Since our domain is all real numbers, we can connect these points based on the pattern that they are forming on the graph which is a line.

5 0
3 years ago
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