Given:
square shape
Perimeter 28 feet
Find its area
A square has 4 equal sides, so perimeter is 4a
Perimeter = 4a
28 ft = 4 a
28 ft / 4 = a
7 = a
One side of the the square is 7 ft.
Area of a square is the measure of one side raised to the power of 2.
A = a²
A = (7 ft)²
A = 49 ft²
Answer:
54
Step-by-step explanation:
To solve problems like this, always recall the "Two-Tangent theorem", which states that two tangents of a circle are congruent if they meet at an external point outside the circle.
The perimeter of the given triangle = IK + KM + MI
IK = IJ + JK = 13
KM = KL + LM = ?
MI = MN + NI ?
Let's find the length of each tangents.
NI = IJ = 5 (tangents from external point I)
JK = IK - IJ = 13 - 5 = 8
JK = KL = 8 (Tangents from external point K)
LM = MN = 14 (Tangents from external point M)
Thus,
IK = IJ + JK = 5 + 8 = 13
KM = KL + LM = 8 + 14 = 22
MI = MN + NI = 14 + 5 = 19
Perimeter = IK + KM + MI = 13 + 22 + 19 = 54
Answer:
8
Step-by-step explanation:
if we take the 2 that is in the R.H.S and put it in L.H.S
it becomes 16÷2=8
C, i dont know dont use my answer unless you know
I find it easiest to use slope-intercept form, or y=mx+b, to do this.
First, find the slope. 6/3 = 2/1 = 2. m = 2.
Next, find the y-intercept. In this case they gave it to you directly. b = -3.
So, the equation would be y = 2x - 3.
