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RSB [31]
3 years ago
13

One number is nine more than twice another. If their sum is decreased by ten, the result is fourteen. Find the numbers.

Mathematics
1 answer:
slava [35]3 years ago
3 0
6 and 9 I think, I'm not 100% sure thugh
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Every year the Lee family has a big family dinner, and everyone brings a mug to exchange. The mugs are put on wooden hangers on
RideAnS [48]

Answer:

21 more mugs were brought this year than last year.

Step-by-step explanation:

We can solve by subtracting the initial amount of mugs from the final amount of mugs.

To find the amount of mugs hung up this year, we will use the equation: m = 12w where m = the number of mugs & w = the number of wooden hangers. The 12 represents the amount of mugs per wooden hanger.

We can plug in 3 for w since 3 wooden hangers were filled up and we would get 12(3) = m = 36 mugs

Now we subtract last year's total mugs hung up from this year's total mugs hung up.

We end up with 36 - 15 = 21

4 0
2 years ago
Given that
yKpoI14uk [10]

Answer:

-6 This is your answer it help you

7 0
3 years ago
Please help and explain
mr_godi [17]
All but -1 <x <1
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4 0
3 years ago
The sum of two consecutive integers is -207
Maru [420]

Answer:

They would be -104 and -103.

Step-by-step explanation:

-103 + (-104)

= -103 - 104

= -207.

3 0
2 years ago
Solve the equation:<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B21%20-%204x%7D%7B9%7D" id="TexFormula1" title="\frac{21 - 4x
schepotkina [342]

Answer:

x = -\frac{12}{5}

Step-by-step explanation:

To solve the equation, isolate x. Whatever you do to isolate x one on side, you must do to the other.  

1) Multiply both sides by 9 to get rid of the fractions.  

\frac{21-4x}{9} +\frac{8x+15}{3} = 2 \\21-4x + 3(8x + 15) =18 \\

2) Distribute the 3 to 8x and 15. Then, combine like terms.

21-4x + 24x + 45 = 18 \\66 + 20x = 18

3) Move the 66 to the other side, subtracting 18 by 66, then divide each side by 20 to finally isolate x.

20x = -48\\x = -\frac{48}{20} \\x =- \frac{12}{5}

Thus, x = -\frac{12}{5}.

3 0
3 years ago
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