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3 years ago

One number is nine more than twice another. If their sum is decreased by ten, the result is fourteen. Find the numbers.

Mathematics

1 answer:

slava [35]3 years ago

3 0

6 and 9 I think, I'm not 100% sure thugh

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19/10 rational or irrational ?

yarga [219]

Definition of a rational number:

A rational number is a number that can be written as fraction of integers.

19/10 is a fraction.

19 and 10 are integers.

19/10 follows exactly the definition of a rational number, so it is rational.

3 0

3 years ago

Please Show Your Work

Morgarella [4.7K]

The area of the trapezoid will be 32.5 square feet. Then the volume of the geometry will be 341.25 cubic feet.

<h3>What is Geometry?</h3>

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

The figure is shown.

Then the volume of the given geometry will be

Volume = Area of the trapezoid × Height

Then the area of the trapezoid will be

$\rm Trapezoid \ area = \dfrac{1}{2} \times (8 + 5) \times 5\\\\\\Trapezoid \ area = 32.5 \ ft^2$

Then the volume of the geometry will be

Volume = 32.5 × 10.5

Volume = 341.25 cubic ft.

More about the geometry link is given below.

brainly.com/question/7558603

#SPJ1

7 0

2 years ago

Find the angle between the given vectors to the nearest tenth of a degree. u = <-5, -4>, v = <-4, -3> (1 point)

sesenic [268]

Angle between $u = -5i-4j , v=-4i-3j$ is $x =0$ ° .

<u>Step-by-step explanation:</u>

We have , two vectors u = <-5, -4>, v = <-4, -3> or , $u = -5i-4j , v=-4i-3j$

We need to find angle between these two vectors . Let's find out:

We know that dot product of two vectors is defined as :

$u.v =|u|(|v|)cosx$ , where x is angle between u & v !

⇒ $u.v =|u|(|v|)cosx$

⇒ $cosx =\frac{u.v}{|u|(|v|)}$

Now , $u.v = (-5i-4j)(-4i-3j)$

⇒ $u.v = (-5i-4j)(-4i)-(-5i-4j)(3j)$

⇒ $u.v = 20+12$ { $i(j) = j(i) =0$ }

⇒ $u.v = 32$

Now , Modulus of any vector $r = xi+yj$ is $|r| = \sqrt{x^{2}+y^{2}}$ So ,

$|u| = \sqrt{(-5)^{2}+(-4)^{2}} = \sqrt{25+16} = \sqrt{41} \\\\|v| = \sqrt{(-4)^{2}+(-3)^{2}} = \sqrt{16+9} = \sqrt{25} = 5$

Putting all these values in equation $cosx =\frac{u.v}{|u|(|v|)}$ we get:

⇒ $cosx =\frac{32}{5(\sqrt{41})}$

⇒ $cos^{-1}(cosx) =cos^{-1}(\frac{32}{5(6.4)})$

⇒ $x =cos^{-1}(1)$ { $cos0 = 1$ }

⇒ $x =0$ °

Therefore , Angle between $u = -5i-4j , v=-4i-3j$ is $x =0$ ° .

8 0

3 years ago

For every $5 Micah saves, his parents give him $10. What is the constant of proportionality

liberstina [14]

When he gets five he gets 2 mor fives

8 0

3 years ago

Pls help with question.

goldfiish [28.3K]

Answer:

5. 39.556

6.5.233

4 b $\frac{13}{2}$

4a $\frac{51}{12}$

7 0

3 years ago