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3 years ago

Express 7.25 in scientific notation

2 answers:

8 0

Considering that scientific notation has to move the decimal over so there is only one digit in the Tens place, that is the scientific notation.

Ghella [55]3 years ago

5 0

7.25 x 10^0 is your answer.
I hope this helped!

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Which of the following gas samples would have the largest number of representative particles at STP? A. 0.520 L SO3 B. 0.10 L Xe

egoroff_w [7]

Answer: The correct option is D.

Explanation: To calculate the larges number of partivles of gas, we will use Avogadro's Law which says that volume of the gas is directly related to the number of moles of gas at constant pressure and temperature.

Mathematically,

$\frac{V_1}{n_1}=\frac{V_2}{n_2}$ ....(1)

The gas which has the largest number of moles, will have the largest number of particles.

We are provided to use STP conditions, which says that

1 mole of a gas occupies 22.4 L of volume.

Initial conditions:

$n_1=1mole$

$V_1=22.4L$

A. 0.520 L of $SO_3$

$V_2=0.520L$

Putting all the values, in equation 1, we get

$\frac{22.4}{1}=\frac{0.520}{n_2}$

$n_2=0.0232moles$

B. 0.10 L of Xe

$V_2=0.10L$

Putting all the values, in equation 1, we get

$\frac{22.4}{1}=\frac{0.10}{n_2}$

$n_2=0.0044moles$

C. 7.0 L of $N_2$

$V_2=7.0L$

Putting all the values, in equation 1, we get

$\frac{22.4}{1}=\frac{7.0}{n_2}$

$n_2=0.3125moles$

D. 12.0 L of Ne

$V_2=12.0L$

Putting all the values, in equation 1, we get

$\frac{22.4}{1}=\frac{12.0}{n_2}$

$n_2=0.5357moles$

Hence, from the above calculations, we see that option D has the largest amount of moles and hence, will have the largest amount of particles.

6 0

4 years ago

Read 2 more answers

HELPPPPP A pearlfish spends the day inside the alimentary tract, or intestines, of a sea cucumber. The fish emerges from the sea

Makovka662 [10]

Answer:

D) Bees and plants or sea anemonies and clownfish.

i think..

Explanation:

5 0

3 years ago

How to balance an unbalanced equation <br><br> C6H6+O2 yields CO2+H2O

storchak [24]

C6H6+15O2=12CO2+6H2O

4 0

4 years ago

Determine the kinetic energy of an 833.0 kg roller coaster car moving at a speed of 20.0 m/s

trasher [3.6K]

Answer:

166,600J

Explanation:

Kinetic energy (K.E), which is the energy due to motion of a body, can be calculated by using the formula;

K.E = 1/2 × m × v²

Where;

K.E = kinetic energy (joules)

m = mass of body (kg)

v = speed or velocity (m/s)

According to this question, the mass of the roller coaster is 833.0 kg while its velocity/speed is 20.0m/s.

K.E = 1/2 × 833 × 20²

K.E = 1/2 × 833 × 400

K.E = 1/2 × 333200

K.E = 166,600

Therefore, the kinetic energy of the roller coaster car is 166,600J.

6 0

3 years ago

1.02 mg of a compound that is known to absorb at 340 nm is dissolved and diluted to 5.00 mL in a volumetric flask. A 1.00 mL ali

Vinvika [58]

Answer:

$6.97 X 10^{-4}$ M

Explanation:

The concentration of the analyte in the 5-mL flask would be $6.97 X 10^{-4}$ M

This is a problem of simple dilution that can be solved using the dilution equation;

C1V1 = C2V2,

where C1 = initial concentration, V1 = initial volume, C2 = final concentration, and V2 = final volume.

<em>In this case, the initial concentration (C1) is not known, the initial volume (V1) is 1.00 mL, the final concentration is 6.97 x 10-5 M, and the final volume is 10.00 mL.</em>

Now, let us make the initial concentration the subject of the formula from the equation above;

C1 = C2V2/V1. Solve for C1 by substituting the other parameters.

C1 = 6.97 x 10-5 x 10/1 = $6.97 X 10^{-4}$ M

7 0

3 years ago