Let r = (t,t^2,t^3)
Then r' = (1, 2t, 3t^2)
General Line integral is:

The limits are 0 to 1
f(r) = 2x + 9z = 2t +9t^3
|r'| is magnitude of derivative vector


Fortunately, this simplifies nicely with a 'u' substitution.
Let u = 1+4t^2 +9t^4
du = 8t + 36t^3 dt

After integrating using power rule, replace 'u' with function for 't' and evaluate limits:
Answer:
Part A : y²(x + 2)(x + 4)
Part B: (x + 4) (x + 4)
Part C: (x + 4) (x - 4)
Step-by-step explanation:
Part A: Factor x²y²+ 6xy²+ 8y²
x²y²+ 6xy²+ 8y²
y² is very common across the quadratic equation , hence
= y² (x² + 6x + 8)
= (y²) (x² + 6x + 8)
= (y²) (x² + 2x +4x + 8)
= (y²) (x² + 2x)+(4x + 8)
= (y²) (x(x + 2)+ 4(x + 2))
= y²(x+2)(x+4)
Part B: Factor x² + 8x + 16
x² + 8x + 16
= x² + 4x + 4x + 16
= (x² + 4x) + (4x + 16)
= x( x + 4) + 4(x + 4)
= (x + 4) (x + 4)
Part C: Factor x² − 16
= x² − 16
= x² + 0x − 16
= x² + 4x - 4x - 16
= (x² + 4x) - (4x - 16)
= x (x + 4) - 4(x + 4)
= (x + 4) (x - 4)
Answer:
The value of the annuity is $326,852.3766.
Step-by-step explanation:
Here is the required formula to find the present value of annuity:
We can find the present value of annuity:

Here:
P = $50,000
n = represents the number of number of periods
r = 0.11

PV = $326,852.3766
The value of the annuity is $326,852.3766 i.e. PV = $326,852.3766.
Keywords: discount rate, present value of annuity
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You can subtract 4 from 13 then subtract 4 again