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3 years ago

Find the equation of the line that is perpendicular to 2x-5y=20 and passes through the point (7,-8

1 answer:

4 0

Hello :
<span>2x-5y=20
calculare the slope:
5y = 2x-20
y =(2/5)x -4
the slope is (2/5).
let : a the slope of the line </span>perpendicular <span>to 2x-5y=20
a×(2/5) = -1
a = -5/2
an equation is : y+8 = (-5/2)(x-7)... (equation in point slope form )</span>

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3 years ago

Can someone answer this question please?

Mekhanik [1.2K]

Steps:
1. calculate the values of y at x=0,1,2. using y=5-x^2
2. calculate the areas of trapezoids (Bottom+Top)/2*height
3. add the areas.

1.
x=0, y=5-0^2=5
x=1, y=5-1^2=4
x=2, y=5-2^2=1
2.
Area of trapezoid 1 = (5+4)/2*1=4.5
Area of trapezoid 2 = (4+1)/2*1=2.5

Total area of both trapezoids = (4.5+2.5) = 7

Exact area by integration:
integral of (5-x^2)dx from 0 to 2
=[5x-x^3/3] from 0 to 2
=[5(2-0)-(2^3-0^3)/3]
=10-8/3
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=7 1/3, slight greater than the estimation by trapezoids.

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3 years ago

Write an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the line described by y=1/2

Marat540 [252]

Given:

The point, (4, -3)

The line,

$y=\frac{1}{2}x+5$

To find an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the given line:

The slope of the line is,

$m=\frac{1}{2}$

Since the given line is parallel to the new line, so the slope will be same for the both.

Using the point-slope formula,

$y-y_1=m(x-x_1)$

Substitute the point and slope we get,

$\begin{gathered} y-(-3)=\frac{1}{2}(x-4) \\ y+3=\frac{1}{2}x-2 \\ y=\frac{1}{2}x-2-3 \\ y=\frac{1}{2}x-5 \end{gathered}$

Hence, the equation in slope-intercept form for the line is,

$y=\frac{1}{2}x-5$

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1 year ago

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3 years ago

Read 2 more answers

Net worth is equal to assets minus liabilities. True or false?

user100 [1]

Answer:

True

Step-by-step explanation:

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