X²-4x+(4/2)²-(4/2)²+13=0
x²-4x+4-4+13=0
-4 should be added
Mark brainliest please
Answer:
22 groups of ten
Step-by-step explanation:
121 plus 116 = 237
237 - 9 = 228
lets split 228 into parts
200
20
8
there are 20 groups of ten in 200
2 groups of ten in 20
and 8 has 0 it is a remainder
20 groups plus 2 groups = 22
22 groups of ten
this probobly isn't the easiest way but I don't know how but this is my thought process.
Given the expression (8+3i)+(-2+i)
We need to simplify it.
(8+3i)+(-2+i)
First we have to remove the parenthesis.
8+3i-2+i
As we know that multiplication of positive and negative is negative.
Now we will add or subtract like terms. Like terms means here i with i and constant term with constant term. So here we will add 3i and i. Also subtract 2 from 8.
8-2 +3i+i
6+4i
We have got the required answer.
The simplified answer is 6+4i.
There are no real solutions.
if you subtract 20 from both sides, you get
x² = -16
You cannot find the square root of a negative number without using i, so there are no real number solutions.
