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statuscvo [17]
3 years ago
10

The force of friction on an object is dependent on two things. what are they?

Physics
1 answer:
ruslelena [56]3 years ago
7 0
1.the kinds of surface
2.the amount of force pushing the surfaces together
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Some help me on this please
satela [25.4K]

Answer:

Changes in the object's momentum (answer D)

Explanation:

A net force will cause an object to change its velocity, and that will affect the object's momentum, which is defined by the product of the object's mass times its velocity.

So, select the last option (D) in the given list.

8 0
2 years ago
This equation is used to calculate the properties of a gas under nonideal conditions.
goblinko [34]

Answer:

Van der Waal's equation

Explanation:

The Van der Waal's equation is use to calculate the properties of a gas under nonideal or real gases conditions.

(P + \frac{an^2}{V^2})(V-nb) = nRT .

Here P, V ,T ,n and R have usual meaning as in the ideal gas equation

that is PV=nRT

with the difference of constant a and b.  a and b are constants representing magnitude of intermolecular attraction  and excluded volume respectively respectively.

5 0
3 years ago
A 50-ohm resistor in a 0.5 Amp circuit produces how much voltage drop?​
ahrayia [7]

25 volts

Explanation:

Use Ohm's law to find the potential drop:

V = IR

= (0.5 A)(50 ohms)

= 25 volts

6 0
2 years ago
Starburst galaxies:
alexgriva [62]

Answer:

are often associated with a galaxy that is colliding with another galaxy.

Explanation:

A starburst galaxy is a galaxy that undergoes very fast formation of stars. The rate at which stars are born is 100 times more than 3 solar masses per year of the Milky Way. The starburst is stage of the formation of a galaxy. After this stage is complete the stars will have used almost all the gas in it. As the star formation rate is very fast the difference between the age of the stars and the galaxy itself is very less. The star formation is triggered by mergers and tidal interactions between gas-rich galaxies.

6 0
3 years ago
A person walks 9.0 km directly east and then turns left and heads directly north for 12.0 km. What is his displacement from the
Readme [11.4K]

Explanation:

Given that,

A person walks 9.0 km directly east and then turns left and heads directly north for 12.0 km.

We need to find his displacement from the starting position.

We know that,

Displacement = shortest path covered

D=\sqrt{9^2+12^2} \\\\D=15\ km

For direction,

\theta=\tan^{-1}(\dfrac{d_y}{d_x})\\\\\theta=\tan^{-1}(\dfrac{12}{9})\\\\= $$53.13^{\circ}

Hence, this is the required solution.

5 0
2 years ago
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