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Naddika [18.5K]
3 years ago
6

A 1.5 kg frictionless pendulum is released from point A at an angle θ of 35 degrees. The speed of the pendulum at point C is 3.4

m/s. What is the length of the pendulum?
A) 3.3m
B) 0.72m
C) 0.59m
D) 8.7m
Physics
1 answer:
sergeinik [125]3 years ago
3 0

The length of the pendulum is 3.3 m.

The given parameters:

  • Mass, m = 1.5 kg
  • Angle, θ = 35⁰
  • Speed, v = 3.4 m/s

<h3>What is principle of conservation of energy?</h3>
  • The principle of conservation of energy states that, the total energy of a system is always conserved.

P.E = K.E

mgh = ¹/₂mv²

gh = ¹/₂v²

g(L - Lcosθ) = ¹/₂v²

gL(1 - cosθ) = ¹/₂v²

L = \frac{v^2}{2g(1- cos\theta)} \\\\L = \frac{(3.4)^2}{2\times 9.8(1 - cos35)} \\\\L = 3.28 \ m\\\\L = 3.3 \ m

Thus, the length of the pendulum is 3.3 m.

Learn more about length of pendulum here: brainly.com/question/8168512

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Answer: A) Force = 3.841*10^-18 N.

B) force (f) is 4.30* 10^12 times greater than the weight (Fg).

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v = final velocity = 6.80*10^5 m/s

u = initial velocity = 2.40 * 10^5 m/s

S= distance covered = 4.8cm = 0.048m

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Since the acceleration of the electron is assumed to be constant, newton's laws of motion are valid.

Thus, recall that

v² = u² + 2aS

(6.80*10^5)² = ( 2.40*10^5)² + 2*a( 0.048)

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40.48* 10^10 = 0.096a

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Force = 3.841*10^-18 N.

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Fg= 9.11*10^-31 * 9.8

Fg = 8.9278* 10^-30 N

By comparing the force and the weight, we have that

F/Fg = 3.841 * 10^-18/8.9278 * 10^-30 = 4.30* 10^12.

This implies that the force (f) is 4.30* 10^12 times greater than the weight (Fg).

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