Answer:
v = 1.7 m/s
Explanation:
Given that,
Initial velocity of the object, u = 1 m/s
Acceleration of the object, a = 1 m/s²
We need to find the velocity of the object after moving 1 m. Let v be the velocity. Using third equation of kinematics to find it i.e.

So, the final velocity of the object is 1.7 m/s.
Answer:
107 m
Explanation:
Convert km/h to m/s:
128.4 km/h × (1000 m / km) × (1 h / 3600 s) = 35.67 m/s
Distance = rate × time
d = 35.67 m/s × 3.0 s
d = 107 m
"Constant velocity" is another way of saying "zero acceleration".
Answer:
calculate the cars acceleration usingv=u+at
Explanation:
m/s. After 5 s the car reaches the bottome of the hill. Its speed at the bottom of the ... accelerating left a rownie. 10. A cart slows down while moving away from the ... does it need to accelerate to a velocity of 20 m/s
Answer:
so in a given orbital there can be 3 electrons.
Explanation:
The Pauli exclusion principle states that all the quantum numbers of an electron cannot be equal, if the spatial part of the wave function is the same, the spin part of the wave function determines how many electrons fit in each orbital.
In the case of having two values, two electrons change. In the case of three allowed values, one electron fits for each value, so in a given orbital there can be 3 electrons.