Explanation:
The given data is as follows.
= 0, = 0, = 0
= 17.0 m, = 2.10 sec
As the force P is constant and the mass "m" of the tool is constant then it means that the acceleration "a" will also be constant.
Now,
=
17.0 = 2.205a
a =
Also, we know that
F =
m =
So, m =
= 1.66 kg
Since, the tool is subject to its weight W and is in free fall. Hence,
10.0 m =
g = 2.411
Hence, weight of tool in Newtonia is as follows.
W = mg
=
= 4.00 N
Hence, weight of the tool on Newtonia is 4.00 N.
And, weight of the tool on the Earth is as follows.
W =
= 23.62 N
Hence, weight of the tool on Earth is 23.62 N.
Answer:
Therefore,
a)
b) I₂ = 2.55 Ampere
c) Power = 30.6 Watts
d) R₁ = 470.58 ohms.
Explanation:
Given:
Let the primary voltage be,
Secondary Voltage,
Secondary Resistance,
To Find:
a)
b) I₂ = ?
c) Power = ?
d) R₁ = ?
Solution:
The ratio of primary to secondary turns of the transformer, is the ratio of primary to secondary Voltage and is given by,
Substituting the values we get
For, rms current for the secondary supply,
Substituting the values we get
Now for average power at load,
Substituting the values we get
Now for resistance connected directly across the source line Power will remain same,
Substituting the values we get
Therefore,
a)
b) I₂ = 2.55 Ampere
c) Power = 30.6 Watts
d) R₁ = 470.58 ohms.
150kmp miles to the second power add all together them together then you get 46 to the 3rd ad 104
Assuming that the magnitude is additive, then you simply have to add the brightness four times. This is because each star has 2 magnitudes of 8.34. As a result, you have to add 4 magnitudes of 8.34. The solution is as follows:
Magnitude = 4(8.34)
Magnitude = 33.36