-6/16 + 1/4= <br> -3/8 -4/8<br> Can I have help with these questions?

Find an m > 0 such that the the equation x^4−(3m+2)x^2+m^2=0 has four real solutions that form an arithmetic sequence.

Aleonysh [2.5K]

Answer:

The value of m is 6.

Step-by-step explanation:

Here, the given equation,

$x^4-(3m+2)x^2+m^2=0$

$x^4+0x^3-(3m+2)x^2+0x+m^2=0$

Let the roots of the equation are a-3b, a-b, a+b and a + 3b, ( they must be form an AP )

Thus, we can write,

$a-3b+a-b+a+b+a+3b=\frac{\text{coefficient of }x^3}{\text{coefficient of }x^4}$

$=\frac{0}{1}=0$

$\implies a=0----(1)$

$(-3b)(-b)+(-b)(b)+(b)(3b)+(3b)(-3b)+(-b)(3b)+(-3b)(b)=\frac{\text{coefficient of }x^2}{\text{coefficient of }x^4}}$

$=\frac{-3m-2}{1}$

$3b^2-b^2+3b^2-9b^2-3b^2-3b^2=-3m-2$

$-10b^2=-3m-2$

$\implies b^2=\frac{3m+2}{10}-----(2)$

$(-3b)(-b)(b)(3b)=\frac{\text{Constant term}}{\text{coefficient of}x^4}= m^2$

$9b^4=m^2$

$9(\frac{3m+2}{10})^2=m^2$

$9(\frac{9m^2+4+12m}{100})=m^2$

$81m^2+36+108m=100m^2$

$-19m^2+108m+36=0$

$19m^2-108m-36=0$

$19m^2-114m+6m-36=0$

$19m(m-6)+6(m-6)=0$

$(19m+6)(m-6)=0$

$\implies m=-\frac{6}{19}\text{ or }m=6$

But m > 0,

Hence, the value of m is 6.

4 0

3 years ago

Please help me answer this question

vfiekz [6]

9514 1404 393

Answer:

the correct answer is marked

Step-by-step explanation:

The graph ranges vertically between 9 and 15, starting at 9 (the minimum) when x=0. The minimum appears again at x=350.

This means the vertical offset is (9+15)/2 = 12, and the amplitude is (15 -9)/2 = 3. The period is 350, so the coefficient of x is (2π/350). All of the answer choices agree on these parameters.

So, the selection comes down to an understanding of how the sine and cosine curves vary. The sine curve starts at zero and increases from there. The cosine curve starts at its maximum (1) and decreases. Here, the curve starts a its minimum and increases, so could be the opposite of the cosine function.

y = -3cos(2πx/350) +12 . . . . . . matches choice C

5 0

3 years ago

Suppose you drive a car 392 miles on one tank of gas. The tank holds 14 gallons of gas. (Assume the car travels the same distanc

RUDIKE [14]

Answer:

Step-by-step explanation:

Suppose you drive a car 392 miles on one tank of gas. The tank holds 14 gallons of gas. This means that

1 gallon of gas would be used to drive 392/14 = 28 miles

a) The number of miles traveled varies directly with the number of gallons of gas used.

Let x =number of gallons of gas you use.

Let y = the number of miles travelled.

Since y varies directly with x, we will introduce a constant of proportionality, k. Therefore,

y = kx

If 28 miles will require 1 gallon of gas, it means

28 = 1×k

k = 28

So y = 28x

b) we want to determine how far you can drive with 3.7 gallons of gas.

x = 3.7

y = 28x = 28×3.7

y = 103.6 miles

6 0

4 years ago

1 quart is equal to 4 cups given this fact what is 8 quarts equivalent to in cups

SVETLANKA909090 [29]

8 quarts is equal to 32 cups :)

5 0

3 years ago

What is the image of (4,-7) after a reflection over the line y=x

snow_lady [41]

Answer:

(-4,7)

Step-by-step explanation:

solved by graphing

3 0

3 years ago

-6/16 + 1/4= -3/8 -4/8 Can I have help with these questions?