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2 years ago

It's 1:00 p.M. And I've driven 120 miles. At 3:00 p.M. I will have driven 208 miles. What is my speed?

Mathematics

2 answers:

bazaltina [42]2 years ago

7 0

Answer:

44 miles/hour

Step-by-step explanation: since speed = distance/time

= 88miles/2hours

=44miles/hour

statuscvo [17]2 years ago

5 0

From 1 pm to 3 pm is 2 hours.

208 miles - 120 mile = 88 miles

You drove 88 miles in 2 hours.

Speed = miles driven / time driven:

88 / 2 = 44 miles per hour

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C. y=3x+1 is the answer.

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2 years ago

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Which expressions are equivalent?

trapecia [35]

Only 3(a−b) and 3a−3b are equivalent

Further explanation:

We have to evaluate each expression to evaluate if the expressions are equivalent or not.

So,

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As we can see that 3(a-b) results in 3a-3b so these are equivalent

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2 years ago

Nico owns 11 instructional piano books. Two are beginner books, six are intermediate books, and three are advanced books. If two

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The probability that he first chooses an advanced book and then chooses a beginner book is 6/121.

<h3>Probability</h3>

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1 year ago

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kotegsom [21]

2- 54:81, 54/81
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2 years ago

Harry is trying to solve the equation 0 = 2x2 − x − 6 using the quadratic formula. He has made an error in one of the steps belo

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<h3><u>Given</u> - </h3>

➙ a quadratic equation in which Harry lagged due to an error made by him, 2x² - x - 6= 0

<h3><u>To solve</u> - </h3>

➙ the given quadratic equation.

<h3><u>Concept applied</u> - </h3>

➙ We will apply the quadratic formula as given in the question. So, let's study about quadratic equation first because we are supposed to apply the formula in equation.

What is quadratic equation?

➙ A quadratic equation in the variable x is an equation of the form ax² + bx + c = 0, where a, b, c are real numbers, a ≠ 0.

Now, what is quadratic formula?

➙The roots of a quadratic equation ax + bx + c = 0 are given by $\sf{\:\frac{-b \pm\: \sqrt {b ^ 2 - 4ac}}{2a}}$ provided b - 4ac ≥ 0.

<h3><u>Solution</u> - </h3>

here as per the given quadratic equation,

a = 2, b = -1 and c = -6

putting in the formula,

$\implies\sf{x=\frac{-(-1) \pm\: \sqrt {(-1)^2 - 4(2)(-6)}}{2(2)}}$

$\implies\sf{x=\frac{1 \pm\: \sqrt {1+48}}{4}}$

$\implies\sf{x=\frac{1 \pm\: \sqrt {49}}{4}}$

$\implies\sf{x=\frac{1 \pm\: 7}{4}}$

Solving one by one,

$\implies\sf{x=\frac{1 + \: 7}{4}}$

$\implies\sf{x=\frac{8}{4}}$

$\implies{\boxed{\bf{x=2}}}$

________________

$\implies\sf{x=\frac{1 - \: 7}{4}}$

$\implies\sf{x=\frac{-6}{4}}$

$\implies{\boxed{\bf{x=\frac{-3}{2}}}}$

________________________________

<em><u>Note</u> - Hey dear user!! You haven't provided the solution which was solved by Harry (A.T.Q). Please go through the solution as it will help you to find the error done by Harry.</em>

Hope it helps!! (:

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