Answer:
The solution of the equations are -6 and 1
Step-by-step explanation:
* <em>Lets explain how to solve the problem</em>
- We want to find the solution of the equation (x + 2) (x + 3) = 12
- <em>At first lets use the Foil method to multiply the two brackets</em>
(x + 2) (x + 3) = (x)(x) + (x)(3) + (2)(x) + (2)(3)
(x + 2) (x + 3) = x² + 3x + 2x + 6 ⇒ add the like term
(x + 2) (x + 3) = x² + 5x + 6
∵ (x + 2) (x + 3) = 12
∴ x² + 5x + 6 = 12
- Subtract 12 from both sides
∴ x² + 5x - 6 = 0
- <em>Factorize the left hand side</em>
∵ x² = (x)(x)
∵ -6 = 6 × -1
∵ 6x + -1x = 5x
∴ (x + 6)(x - 1) = 0
- <em>Lets use the zero product property </em>
∵ (x + 6)(x - 1) = 0
∴ x + 6 = 0 ⇒ <em>OR</em> ⇒ x - 1 = 0
∵ x + 6 = 0
- Subtract 6 from both sides
∴ x = -6
∵ x - 1 = 0
- Add 1 to both sides
∴ x = 1
∴ The solution of the equations are -6 and 1
Answer:
.03
Step-by-step explanation:
.03 would be 3% where all the others are 30% hope this helped!
Answer:
137.12
Step-by-step explanation:
Density = mass/volume
Density = 3.51
Mass = 481.3
Thus: 481.3/3.51 = 137.122507123
Step-by-step explanation:
In triangle
x²=5²+12²
x²=25+144
x²=169
x= root of 169
x=13
Answer:
So, the required width of rectangular piece of aluminium is 8 inches
Step-by-step explanation:
We are given:
Perimeter of rectangular piece of aluminium = 62 inches
Let width of rectangular piece of aluminium = w
and length of rectangular piece of aluminium = w+15
We need to find width i.e value of x
The formula for finding perimeter of rectangle is: 
Now, Putting values in formula for finding Width w:
After solving we get the width of rectangular piece :w = 8
So, the required width of rectangular piece of aluminium is 8 inches
