The net force on the quarterback when he is hit by two linebackers running eastwards is 255N.
Force is a vector quantity, we must recall that if two forces act in the same direction, we obtain the net force by adding the two forces together. If two forces act in opposite direction, we obtain the net force by subtracting the forces from each other.
Since the both linebackers are running East, the net force is obtained as; 105 N + 150 N = 255 N.
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Frequent use of pesticides
Answer:
This is through the process of methylation and phosphorylation of histones tails.
Explanation:
The addition of a methyl group to the amino acid of the histones of the nucleosomes that compacted DNA in the nucleus is called mehtylation, while the addtion of phodpahte is phosphorylation
Its effects on gene expression depends on the number of <u> methyl groups, and type of amino acid that methylated. During transcription. </u>
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The DNA double strands are compacted and therefore hidden from transcription factors and enzymes of transcription by the hitones tails of the neuclosomes, Methylation weaken the binding bonds between the tails and DNA structure ; thereby aiding the uncoiling of DNA from the tails.(nucleosomes).This chemical reaction aided DNA strands exposure to transcription factors and enzymes, for initiation of transcription. This explains the dyanmic activity of methylation
Futhermore phophorylation also favours unwrapping of DNA, by imitating modifying enzymes e.g H3Y41E and H3T45E and convert it to→→ H3Y41phopspahte to aid DNA unwrapping and accessibility to transcription factors and RNA polymerase Enzymes,
By examining the F1 complex of ATP synthase which is from Bovine heart mitochondria. Then we should ask what prevents F1 complex from rotating with Fo c-ring complex?. It is bound to the central stalk. F1 rotates with Fo c-ring complex and nothing prevents it. The mitochondrial membrane is where Fo c-ring is bounded. Stationary "a" subunit of Fo is where the stator which is connected to it bounds.
In conclusion, we will say that the answer is, it is bounded by the stator, which is corrected to the stationary "a" subunit of Fo.
The ring-shaped C subunits form the rotor of the F1FO complex. FOF1 is bound to the central stalk, Therefore, it prevents it from rotation which is during the translocation of protons
I think none of the above...
