Answer:
Technician A
Explanation:
Ohms law: I= E/R so rest resistance must be present along with E/potential difference. Even if just wire shorted together there is resistance but very little.
Tech B: Again ohms law. Current flow is directly proportional to the voltage and inversely proportional to R (resistance or impedance).
Answer:
C
Explanation:
I COULD be wrong, i'm not sure but im confident its c
Answer:
See explaination
Explanation:
We can describe Aspiration Effect as a phenomenon of providing an allowance for the release of air from the mold cavity during the metal pouring.
See the attached file for detailed solution of the given problem.
Answer:
2074.2 KW
Explanation:
<u>Determine power developed at steady state </u>
First step : Determine mass flow rate ( m )
m / Mmax = ( AV )₁ P₁ / RT₁ -------------------- ( 1 )
<em> where : ( AV )₁ = 8.2 kg/s, P₁ = 0.35 * 10^6 N/m^2, R = 8.314 N.M / kmol , </em>
<em> T₁ = 720 K . </em>
insert values into equation 1
m = 0.1871 kmol/s ( mix )
Next : calculate power developed at steady state ( using ideal gas tables to get the h values of the gases )
W( power developed at steady state )
W = m [ Yco2 ( h1 - h2 )co2
Attached below is the remaining part of the detailed solution
Answer:
W=2 MW
Explanation:
Given that
COP= 2.5
Heat extracted from 85°C
Qa= 5 MW
Lets heat supplied at 150°C = Qr
The power input to heat pump = W
From first law of thermodynamics
Qr= Qa+ W
We know that COP of heat pump given as
![COP=\dfrac{Qr}{W}](https://tex.z-dn.net/?f=COP%3D%5Cdfrac%7BQr%7D%7BW%7D)
![2.5=\dfrac{5}{W}](https://tex.z-dn.net/?f=2.5%3D%5Cdfrac%7B5%7D%7BW%7D)
![2.5=\dfrac{5}{W}](https://tex.z-dn.net/?f=2.5%3D%5Cdfrac%7B5%7D%7BW%7D)
W=2 MW
For Carnot heat pump
![COP=\dfrac{T_2}{T_2-T_1}](https://tex.z-dn.net/?f=COP%3D%5Cdfrac%7BT_2%7D%7BT_2-T_1%7D)
![2.5=\dfrac{T_2}{T_2-(273+85)}](https://tex.z-dn.net/?f=2.5%3D%5Cdfrac%7BT_2%7D%7BT_2-%28273%2B85%29%7D)
2.5 T₂ - 895= T₂
T₂=596.66 K
T₂=323.6 °C