All categories

3 years ago

How large a force is required to accelerate a 1300 kg car from rest to a speed of 20 m/s in a distance of 80 m?

Engineering

2 answers:

topjm [15]3 years ago

7 0

F=m*a

F=80*20

F =1600 ans"

Stolb23 [73]3 years ago

5 0

Answer: basically we are asked to find it's force and the formula that helps us to find force is Force= Mass× Acceleration

so let's put out the given and what we need to find

GIVEN. Solution

F=m.a

Mass= 1300. F=1300kg×20m/s

speed (Acceleration)=20m/2. F=26000Kg.m/s

Force=? F=26000N

N stands for Newton and the reason that it comes Newton is because it is the SI-unit of Force and the result of kg×m/s.

You might be interested in

How does a carburetor work?

Pachacha [2.7K]

Answer:

Air flows into the top of the carburetor from the car's air intake, passing through a filter that cleans it of debris. When the throttle is open, more air and fuel flows to the cylinders so the engine produces more power and the car goes faster. The mixture of air and fuel flows down into the cylinders.

Explanation:

4 0

4 years ago

Ayuda con este problema de empuje y principio de arquimedes.

il63 [147K]

Answer:

El principio de arquimedes es un principio de la hidroestática que explica lo que experimenta un cuerpo ... la teoría y después como es costumbre pasaremos a ver problemas resueltos sobre éste principio. ... Si la magnitud del peso del cuerpo es menor a la magnitud de empuje. ... Alguien me ayuda con este Ejercicio :.

Explanation:

7 0

3 years ago

An engine operates on gasoline (LHV=44 MJ/kg) with a brake thermal efficiency of 37.9 % What is the brake specific fuel consumpt

scZoUnD [109]

Answer:

$s =0.21\ kg/Kw.hr$

Explanation:

Given that

Calorific value (CV) = 44 MJ/Kg

CV= 44,000 KJ/kg

Brake thermal efficiency(η) = 37.9 %

We know that

$\eta =\dfrac{BP}{\dot{m_f}\times CV}$

Where BP is the brake power

$\eta =\dfrac{BP}{\dot{m_f}\times CV}$

$0.379 =\dfrac{BP}{\dot{m_f}\times 44000}$

$\dfrac{BP}{\dot{m_f}}=16676$

Brake specific fuel consumption (s)

$s =\dfrac{\dot{m_f}}{BP}$

$s =\dfrac{3600\times \dot{m_f}}{BP}$

$s =\dfrac{3600}{16,676}\ kg/Kw.hr$

$s =0.21\ kg/Kw.hr$

7 0

3 years ago

A hair dryer is basically a duct of constant diameter in which a few layers of electric resistors are placed. A small fan pulls

Inessa05 [86]

Answer:

the percent increase in the velocity of air is 25.65%

Explanation:

Hello!

The first thing we must consider to solve this problem is the continuity equation that states that the amount of mass flow that enters a system is the same as what should come out.

m1=m2

Now remember that mass flow is given by the product of density, cross-sectional area and velocity

(α1)(V1)(A1)=(α2)(V2)(A2)

where

α=density

V=velocity

A=area

Now we can assume that the input and output areas are equal

(α1)(V1)=(α2)(V2)

$\frac{V2}{V1} =\frac{\alpha1 }{\alpha 2}$

Now we can use the equation that defines the percentage of increase, in this case for speed

$i=(\frac{V2}{V1} -1) 100$

Now we use the equation obtained in the previous step, and replace values

$i=(\frac{\alpha1 }{\alpha 2} -1) 100\\i=(\frac{1.2}{0.955} -1) 100=25.65$

the percent increase in the velocity of air is 25.65%

6 0

3 years ago

g . 3. For each of the following statements Write the statement as an English sentence that does not use the symbols for quan 2.

lubasha [3.4K]

Answer:

(a)

( ∃x ∈ Q) ( x > √2)

There exists a rational number x such that x > √2.

( ∀x ∈ Q) ( ( x ≤ √2)

For each rational number x, x ≤ √2.

(b)

(∀x ∈ Q)(x² - 2 ≠ 0).

For all rational numbers x, x² - 2 ≠ 0

( ∃x ∈ Q ) ( x² - 2 = 0 )

There exists a rational number x such that x² - 2 = 0

(c)

(∀x ∈ Z)(x is even or x is odd).

For each integer x, x is even or x is odd.

( ∃x ∈ Z ) (x is odd and x is even)

There exists an integer x such that x is odd and x is even.

(d)

( ∃x ∈ Q) ( √2 < x < √3 )

There exists a rational number x such that √2 < x < √3

(∀x ∈ Q) ( x ≤ √2 or x ≥ √3 )

For all rational numbers x, x ≤ √2 or x ≥ √3.

3 0

3 years ago