Answer:
1425.78 N.m
Explanation:
Moments of force is calculated as ;
Moments= Force * distance
M= F*d
The S.I unit for moment of force is Newton-meter (N.m)
Given in the question;
Force = 72 lbs
1 pound = 4.45 N
72 lbs = 4.45 * 72=320.4 N
Distance= 15 ft
1ft= 0.3048 m
15 ft = 15*0.3048 = 4.57 m
d= 4.57 m
M= F*d
M=320.4*4.57 =1425.78 N.m
I think that the answer would be B or C
The largest tensile force that can be applied to the cables given a rod with diameter 1.5 is 2013.15lb
<h3>The static equilibrium is given as:</h3>
F = P (Normal force)
Formula for moment at section
M = P(4 + 1.5/2)
= 4.75p
Solve for the cross sectional area
Area =
d = 1.5
= 1.767 inches²
<h3>Solve for inertia</h3>
= 0.2485inches⁴
Solve for the tensile force from here
30x10³ =
30000 = 14.902 p
divide through by 14.902
2013.15 = P
The largest tensile force that can be applied to the cables given a rod with diameter 1.5 is 2013.15lb
Read more on tensile force here: brainly.com/question/25748369
Answer:
Final length of the rod = 13.90 in
Explanation:
Cross Sectional Area of the polythene rod, A = 0.04 in²
Original length of the polythene rod, l = 10 inches
Tensile modulus for the polymer, E = 25,000 psi
Viscosity,
Weight = 358 lbs - f
time, t = 1 hr = 3600 sec
Stress is given by:
Based on Maxwell's equation, the strain is given by:
Strain = Extension/(original Length)
0.39022 = Extension/10
Extension = 0.39022 * 10
Extension = 3.9022 in
Extension = Final length - Original length
3.9022 = Final length - 10
Final length = 10 + 3.9022
Final length = 13.9022 in
Final length = 13.90 in
Explanation:
He would work on the thing like in the method you work on your question.