Answer:
metals, composite, ceramics and polymers.
Explanation:
The four categories of engineering materials used in manufacturing are metals, composite, ceramics and polymers.
i) Metals: Metals are solids made up of atoms held by matrix of electrons. They are good conductors of heat and electricity, ductile and strong.
ii) Composite: This is a combination of two or more materials. They have high strength to weight ratio, stiff, low conductivity. E.g are wood, concrete.
iii) Ceramics: They are inorganic, non-metallic crystalline compounds with high hardness and strength as well as poor conductors of electricity and heat.
iv) Polymers: They have low weight and are poor conductors of electricity and heat
A good visual lead is 20-30 seconds from the front of the vehicle, focusing in the center of the path of travel. Searching 20 to 30 seconds ahead, gives you time to assess within the next ..12-15 seconds, actions you may need to take to control an approaching risk.
Discussion:
Keeping eye focus centered in a path of travel at an interval of 20 to 30 seconds away from the vehicle is critical to gaining enough info. as possible in the driving scene. Good targeting sets up good sight lines for referencing and good peripheral fields for observing changes.
- It is important to look ahead 12-15 seconds into your target area as one drives. Compromise. space by giving as much space to the greater of two hazards.
Read more on driving visual leads:
brainly.com/question/7067386
Answer:
the value of conductivity in IP is 
Explanation:
Given that
Thermal conductivity K=14.54 W/m.K
This above given conductivity is in SI unit.
SI unit IP unit Conversion factor
m ft 0.3048
W Btu/hr 0.293
The unit of conductivity in IP is Btu./ft.hr.F.
Now convert into IP divided by 1.73 factor.
So
So the value of conductivity in IP is
Answer:
Explanation:
Given that : -
The desirable limit is 500 mg / l , but
allowable upto 2000 mg / l.
The take volume is V = 160.000 m3
V = 160 , 000 x 103 l
The crainage gives 150 mg / l and lake has initialy 100 mg / l
Code of tpr frpm drawn = 150 x 60, 000 x 1000
Ci = 9000 kg / gr
Cl = 100 x 160,000 x 1000
Cl = 16, 000 kg
Since allowable limit = 2000 mg / l
Cn = ( 2000 x 160, 00 x 1000 )
= 320, 000 kg
so, each year the rate increases, by 9000 kg / yr
Read level = ( 320, 000 - 16,000 )
Li = 304, 000 kg
Tr=<u>304,000</u>
900
=33.77
Answer:
T=120.04°C
Explanation:
Given that
L= 7.5 cm
q = 105 W/m³
T∞=120°C
h=750 W/m²K
K=20 W/mK
Here given that one side of the wall is insulated that is why the maximum temperature will be at the insulated surface.
The total heat transfer from the wall
Q= q A L
Q= 150 x 0.075 A
Q=7.875 A W
A=Area of wall
Now the total thermal resistance R
We also know that
Temperature at insulated side = T
T=120.04°C
