Answer:
The differential equation and the boundary conditions are;
A) -kdT(r1)/dr = h[T∞ - T(r1)]
B) -kdT(r2)/dr = q'_s = 734.56 W/m²
Explanation:
We are given;
T∞ = 70°C.
Inner radii pipe; r1 = 6cm = 0.06 m
Outer radii of pipe;r2 = 6.5cm=0.065 m
Electrical heat power; Q'_s = 300 W
Since power is 300 W per metre length, then; L = 1 m
Now, to the heat flux at the surface of the wire is given by the formula;
q'_s = Q'_s/A
Where A is area = 2πrL
We'll use r2 = 0.065 m
A = 2π(0.065) × 1 = 0.13π
Thus;
q'_s = 300/0.13π
q'_s = 734.56 W/m²
The differential equation and the boundary conditions are;
A) -kdT(r1)/dr = h[T∞ - T(r1)]
B) -kdT(r2)/dr = q'_s = 734.56 W/m²
Answer:
b
Explanation:
i think do kill me if im wrong
Answer:
The number of inputs processed by the new machine is 64
Solution:
As per the question:
The time complexity is given by:
where
n = number of inputs
T = Time taken by the machine for 'n' inputs
Also
The new machine is 65 times faster than the one currently in use.
Let us assume that the new machine takes the same time to solve k operations.
Then
T(k) = 64 T(n)
k = 64n
Thus the new machine will process 64 inputs in the time duration T
