Answer:
1.53 m/s²
Explanation:
Given:
Δx = 400 m
v₀ = 0 m/s
v = 35 m/s
Find: a
v² = v₀² + 2aΔx
(35 m/s)² = (0 m/s)² + 2a (400 m)
a = 1.53 m/s²
The centripetal acceleration is 
Explanation:
The centripetal acceleration for an object in circular motion is given by

where
v is the linear speed
r is the radius of the circle
The body in the problem cover half of revolution in
t = 10 s
And the corresponding linear distance covered is
L = 10 m
which corresponds to half of the circumference, so

From this equation we find the radius of the circle:
[m]
While the linear speed is:

Therefore, the centripetal acceleration is

Learn more about circular motion:
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The oxygen will flow out of the tire,
which causes the tire to become flat.
Answer:
The displacement of the train in this time period is 2,616.86 m.
Explanation:
A Uniformly Varied Rectilinear Motion is Rectilinear because the mobile moves in a straight line, Uniformly because of there is a magnitude that remains constant (in this case the acceleration) and Varied because the speed varies, the final speed being different from the initial one.
In other words, a motion is uniformly varied rectilinear when the trajectory of the mobile is a straight line and its speed varies the same amount in each unit of time (the speed is constant and the acceleration is variable).
An independent equation of useful time in this type of movement is:
<em>Expression A</em>
where:
- vf = final velocity
- vi = initial velocity
- a = acceleration
- d = distance
The equation of velocity as a function of time in this type of movement is:
vf=vi + a*t
So the velocity can be calculated as: 
In this case:
- vf=42.4 m/s
- vi=27.5 m/s
- t=75 s
Replacing in the definition of acceleration: 
a=0.199 m/s²
Now, replacing in expression A:

Solving:

d= 2,616.86 m
<u><em>The displacement of the train in this time period is 2,616.86 m.</em></u>
Answer:
194 V/m
Explanation:
In order to find electric field, we can use the formula of power density
i.e Pd = E^2 / Z
where:
Pd = power density in W/m^2
E = electric field strength in V/m
Z = impedance of free space = 120 * π
E = sqrt(Pd * Z)
-----> re-arranging it for E
before solving, convert Pd unit into W/m^2
Pd= 5mW/cm^2 = 50 W/m^2
Solving for E:
E= sqrt(50 * 120 * π)
E = 137.3 V/m
the above value is RMS value
In order to find the peak amplitude of the oscillating field will therefore be 137.3 * sqrt(2) = 194 V/m