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Alex Ar [27]
3 years ago
15

Suppose you are investigating how the day ends hamsters affect how much they run on the hamster wheel. In order to control the e

xperiment which of these should you do?
A. Change only the diet of each hampster.

B. Give all the hamsters the exact same diet.

C. Only allow some hampsters to run on the wheel.

D. Compare the behavior of hamsters and gerbils

Physics
2 answers:
Rzqust [24]3 years ago
7 0

Answer:

B

Explanation:

If you want to control the experiment, you want to make sure that no outside factor could potentially influence your results.

Hence, changing the diet of a hamster would significantly alter any results you may collect.

For example, if you allow hamster A to eat a nutritious diet, while not giving a proper diet to hamster B. Hamster A will perform better, and run further and for longer, because he has more energy.

The answer is B, because you want to make sure no hamster is at an advantage.

aksik [14]3 years ago
5 0
The answer is C because you need non running hamsters to compare running hamsters with.
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A 1.75 kg box is pushed with a 8.35 N force across ground where k = 0.267. What is the net force on the box?
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The net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.

To find the answer, we have to know more about the basic forces acting on a body.

<h3>How to find the net force on the box?</h3>
  • Let us draw the free body diagram of the given box with the data's given in the question.
  • From the diagram, we get,

                                 N=mg\\F_t=ma\\F_t=F-f

where, N is the normal reaction, mg is the weight of the box, F_t is the net force, f is the kinetic friction.

  • We have the expression for kinetic friction as,

                      f=kN=kmg=0.267*1.75*9.8= 4.58N

  • Thus, the net force will be,

                        F_t= 8.35-4.58=3.77N

Thus, we can conclude that, the net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.

Learn more about the basic forces on a body here:

brainly.com/question/28061293

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