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Natali [406]
3 years ago
9

As a object falls from a high-flying stationary helicopter, its velocity increases and its acceleration ____.

Physics
2 answers:
photoshop1234 [79]3 years ago
7 0
Increase by 6 then by a number of 3
11Alexandr11 [23.1K]3 years ago
3 0
I think it’ll increase? maybe stay the same?
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Someone help me asap!
bogdanovich [222]

Answer:the answer would be B, heavy rainfall causes a landslide on the side of the mountain.

Explanation:

Hydrosphere is all water or liquid elements in the earths atmosphere and geosphere is the solid parts, such as rock.

4 0
4 years ago
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A point charge of 5.0 x 10^-7 C moves to the right at 2.6 x 10^5 m/s in a magnetic field that is directed into the screen and ha
-BARSIC- [3]

The magnitude of the magnetic force acting on the charge is 2.34×10⁻³ N.

<h3>What is magnetic force?</h3>

A magnetic force is the force that act in a magnetic field.

To calculate the magnetic force, we use the formula below.

Formula:

  • F = qvB.........Equation 1

Where:

  • F = magnetic force
  • q = point charge
  • v = Velocity of the the charge
  • B = Field strength

From the question,

Given:

  • q = 5.0×10⁻⁷ C
  • v = 2.6×10⁵ m/s
  • B = 1.8×10⁻² T

Substitute these values into equation 2

  • F = (5.0×10⁻⁷)(2.6×10⁵)(1.8×10⁻²)
  • F = 23.4×10⁻⁴
  • F = 2.34×10⁻³ N

Hence, the magnitude of the magnetic force acting on the charge is 2.34×10⁻³ N.

Learn more about magnetic force here: brainly.com/question/2279150

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5 0
2 years ago
What is the numerical value, in meters per second squared, of the acceleration of an object experiencing true free fall?
Nuetrik [128]

Answer:

9.8 m/s/s

Explanation:

The numerical value, in meters per second squared, of the acceleration of an object experiencing true free fall is 9.8 m/s/s. This is called the acceleration due to gravity.

8 0
3 years ago
Read 2 more answers
A shopper does 157 J of work pushing a cart with 10.9 N force
Tanzania [10]

The cart travelled a distance of 14.4 m

Explanation:

The work done by a force when pushing an object is given by:

W=Fd cos \theta

where:

F is the magnitude of the force

d is the displacement

\theta is the angle between the direction of the force and the displacement

In this problem we have:

W = 157 J is the work done on the cart

F = 10.9 N is the magnitude of the force

\theta=0^{\circ}, assuming the force is applied parallel to the motion of the cart

Therefore we can solve for d to find the distance travelled by the cart:

d=\frac{W}{F cos \theta}=\frac{157}{(10.9)(cos 0)}=14.4 m

Learn more about work:

brainly.com/question/6763771  

brainly.com/question/6443626  

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4 0
3 years ago
A 650-kg elevator starts from rest. It moves upward for 3.00 s with constant acceleration until it reaches its cruis- ing speed
Nataly_w [17]

Answer: P=5573.43\ W

Explanation:

Given

Mass of the elevator is M=650\ kg\\\

Time period of ascension t=3\ s

cruising speed v=1.75\ m/s

Distance moved by elevator during this time

Suppose Elevator starts from rest

\Rightarrow v=u+at\\\Rightarrow 1.75=0+a(3)\\\Rightarrow a=0.583\ s

Distance moved

\Rightarrow h=ut+0.5at^2\\\Rightarrow h=0+0.5\times 0.5833\times (3)^2\\\Rightarrow h=2.62\ m

Gain in Potential Energy is

\Rightarrow E=mgh\\\Rightarrow E=650\times 9.8\times 2.62\\\Rightarrow E=16,720.3\ N

Average power during this period is

\Rightarrow P=\dfrac{E}{t}\\\\\Rightarrow P=\dfrac{16,720.3}{3}\\\\\Rightarrow P=5573.43\ W

7 0
3 years ago
Read 2 more answers
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