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3 years ago

Pls Solve, if you show work or explain i will mark brainliest!!

2 answers:

7 0

Deal with the letters one by one, first, look at m, the exponent in the denominator is 5, the exponent in the numerator is -2, 5 is larger than -2, so the letter stay in the denominator, 5-(-2)=7, that is m to the 7th power.
do the same with n and p, the final result is: n^10 on the top, m^7p^16 on the bottom.

lina2011 [118]3 years ago

4 0

Grant him brainliest as you said!! ;)

Then you can delete my answer!!

You might be interested in

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

fenix001 [56]

Answer:

2, 7, 114

Step-by-step explanation:

(3 + 0.5x)(38 - 4x)

114 + 19x - 12x - 2x²

-2x² + 7x + 114

7 0

3 years ago

In kite ABCD, mZBAE = 28º and mZBCE = 58°. Find mZABE. B E А С D mLABE =

Digiron [165]

Answer:

m∠ABE = 62°

Step-by-step explanation:

Since, the given quadrilateral is a kite, diagonals will intersect at 90°.

Therefore, m∠AEB = m∠CEB = 90°

m∠BAE = 28° [Given]

m∠BCE = 58° [Given]

From ΔABE,

m∠BAE + m∠BEA + m∠ABE = 180°

28° + 90° + m∠ABE = 180°

m∠ABE = 180° - 118°

= 62°

Therefore, measure of angle ABE = 62°.

3 0

3 years ago

a bank receives a deposit for $30000. If the bank has a 10 percent reserve requirement approximately how much money could be ini

Elodia [21]

It might be 30000 maybe

5 0

3 years ago

A perpendicular bisector, , is drawn through point C on .

Liula [17]

Answer:

The x-intercept of CD is B(18/5,0). The point C(32,-71) lies on the line CD.

Step-by-step explanation:

the x-intercept of CD is[ A(3,0) B(18/5,0) C(9,0) D(45/2,0) ] . Point [ A(-52,117) B(-20,57) C(32,-71) D(-54,-128) ] lies on CD.

Given :

CD is perpendicular bisector of AB.

The coordinates of point A are (-3, 2) and the coordinates of point B are (7, 6).

C is the midpoint of AB.

$C=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})=(\frac{7-3}{2},\frac{2+6}{2})=(2,4)$

The coordinates of C are (2,4).

Line AB has a slope of: $m_1=\frac{y_2-y_1}{x_2-x_1}=\frac{6-2}{7-(-3)}=\frac{4}{10}=\frac{2}{5}$

The product of slopes of two perpendicular lines is -1. Since the line CD is perpendicular to AB, therefore the slope of CD : $m_2=-\frac{5}{2}$

The point slope form of a line is given by:

$y-y_1=m(x-x_1)$

The slope of line CD is $-\frac{5}{2}$ and the line passing through the point (2,4), the equation of line CD can be written as:

$y-4=-\frac{5}{2}(x-2)\\y=-\frac{5}{2}x+5+4\\y=-\frac{5}{2}x+9 .... (1)$

The equation of CD is $y=-\frac{5}{2}x+9$

In order to find the x-intercept, put y=0.

$0=-\frac{5}{2}x+9\\\frac{5}{2}x=9\\x=\frac{18}{5}$

Therefore the x-intercept of CD is B(18/5,0).

Put x=-52 in eq(1).

$y=-\frac{5}{2}(-52)+9=139$

Put x=-20 in eq(1).

$y=-\frac{5}{2}(-20)+9=59$

Put x=32 in eq(1)

$y=-\frac{5}{2}(32)+9=-71$

Put x=-54 in eq1).

$y=-\frac{5}{2}(-54)+9=144$

Thus, only point (32,-71) satisfies the equation of CD. Therefore the point C(32,-71) lies on the line CD.

8 0

4 years ago

Given n > 0, Adam conjectured that 6" Which value is a counterexample to Adam's conjecture?

miv72 [106K]

Answer:

n = 4

Step-by-step explanation:

Unit: 1.14 Unit Test: Introduction to Logic and Euclidean Geometry - Part 1

5 0

2 years ago