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valina [46]
3 years ago
13

Which of the following numbers is read, "six thousand, nine hundred seven"?

Mathematics
2 answers:
Igoryamba3 years ago
6 0
6907 is the correct answer
Murrr4er [49]3 years ago
3 0
Answer: 6907
Six thousand= 6000
Nine hundreds=900
Seven= 7
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12 belongs to which set(s) of numbers?o Natural Numbers, Whole Numbers, and Integers onlyNatural Numbers and Whole Numbers onlyo
erastova [34]

Integers are written without no fractional components so 12 is an integer .

Natural numbers are positive numbers just like the number we count. 12 is a natural number.

Rational numbers

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11 months ago
What is the acceleration of an object in air that has a velocity of Om/s?
pochemuha

Answer:

9.8m/s^2

Step-by-step explanation:

5 0
2 years ago
Given: ABCD is a trapezoid, AC ⊥ CD AB = CD, AC=the square root of 75 , AB = 5 Find: AABCD
Ugo [173]

In this attached picture according to the conditions of the problem we have an isosceles trapezoid and since we know that legs are equal (AD=BC=5 cm), we have to calculate bases and height in order to find the area. Working with the triangle BCD, we apply Pythagoras theorem and find that CD = \sqrt{75+25} = 10 cm. Since BDC is a right triangle, applying theorem for the area of triangles, we find that \frac{1}{2} * BF =  \frac{1}{2} * 5 * \sqrt{75} and BF= 0.5\sqrt{75}. Since ABCD is an isosceles trapezoid, triangles ADE and BFC are congruent with Angle Side Angle theorem. Then, DE=FC and with the help of Pythagoras theorem, DE=FC=2.5 cm. Then, AB=EF=5 cm and the area of the trapezoid is  A= BF *  \frac{AB+CD}{2} = 0.5  \sqrt{75}  * \frac{5+10}{2} = 18.75 \sqrt{3}   cm^{2}

3 0
3 years ago
Find measure dbc <br> 19<br> 22<br> 23<br> 161 <br> HELP !!!
uysha [10]
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4 0
3 years ago
Suppose that a cyclist began a 476
mojhsa [17]
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we know the rate of the car is faster... so if the cyclist rate is say "r", then the car's rate is r+33.2

thus    \bf \begin{array}{lccclll}&#10;&distance&rate&time\\&#10;&-----&-----&-----\\&#10;\textit{eastbound cyclist}&d&r&8.5\\&#10;\textit{westbound car}&476-d&r+33.2&8.5&#10;\end{array}\\\\&#10;-----------------------------\\\\&#10;\begin{cases}&#10;\boxed{d}=8.5r\\\\&#10;476-d=(r+33.2)8.5\\&#10;----------\\&#10;476-\boxed{8.5r}=(r+33.2)8.5&#10;\end{cases}

solve for "r", to see how fast the cyclist was going

what about the car? well, the car's rate is r + 33.2
6 0
3 years ago
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