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valina [46]
3 years ago
13

Which of the following numbers is read, "six thousand, nine hundred seven"?

Mathematics
2 answers:
Igoryamba3 years ago
6 0
6907 is the correct answer
Murrr4er [49]3 years ago
3 0
Answer: 6907
Six thousand= 6000
Nine hundreds=900
Seven= 7
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I need help with math ​
Sonbull [250]

Answer:

6 is answer...............

6 0
2 years ago
Please answer part b and part C!
max2010maxim [7]
Hey! Please do not use that link to download the answers. It’s fake and it’s a scam, they commented that on mine to so don’t do it
6 0
2 years ago
Read 2 more answers
Is UVW=Xyz?if so, name the postulate that applies
aivan3 [116]

By critically observing the two triangles, we can deduce that they: B. might not be congruent.

<h3>The properties of similar triangles.</h3>

In Geometry, two triangles are said to be similar when the ratio of their corresponding sides are equal in magnitude and their corresponding angles are congruent.

By critically observing the two triangles, we can logically deduce that the three angles of both triangles are congruent in accordance with AAA similarity postulate:

  • <U ≅ <X
  • <V ≅ <Y
  • <W ≅ <Z

However, AAA isn't a congruence postulate and as such all similar triangles might not be congruent.

Read more on congruency here: brainly.com/question/11844452

#SPJ1

4 0
1 year ago
On a coordinate plane, 2 polygons are shown. Polygon A B C D has points (1, negative 6), (5, negative 6), (6, negative 2), and (
irga5000 [103]

Answer:

The correct option is;

Use a scale factor of 2

Step-by-step explanation:

The parameters given are;

A = (1, -6)

B = (5, -6)

C = (6, -2)

D = (0, -2)

A'' = (1.5, 4)

B'' = (3.5, 4)

C'' = (4, 2)

D'' = ( 1, 2)

We note that the length of side AB in polygon ABCD = √((5 -1)² + (-6 - (-6))²) = 4

The length of side A''B'' in polygon A''B''C''D'' = √((3.5 -1.5)² + (4 - 4)²) = 2

Which gives;

AB/A''B'' = 4/2 = 2

Similarly;

The length of side BC in polygon ABCD = √((6 -5)² + (-2 - (-6))²) = √17

The length of side B''C'' in polygon A''B''C''D'' = √((4 -3.5)² + (2 - 4)²) = (√17)/2

Also we have;

The length of side CD in polygon ABCD = √((6 -0)² + (-2 - (-2))²) = 6

The length of side C''D'' in polygon A''B''C''D'' = √((4 -1)² + (2 - 2)²) = 3

For the side DA  and D''A'', we have;

The length of side DA in polygon ABCD = √((1 -0)² + (-6 - (-2))²) = √17

The length of side D''A'' in polygon A''B''C''D'' = √((1.5 -1)² + (4 - 2)²) = (√17)/2

Therefore the Polygon A B C D can be obtained from polygon A''B''C''D'' by multiplying each side of polygon A''B''C''D'' by 2

The correct option is therefore;

Use a scale factor of 2.

3 0
3 years ago
Read 2 more answers
Prove that angles opposite to equal sides of an isosceles triangle are equal.
ZanzabumX [31]

Answer:

Step-by-step explanation:

Take a triangle ABC, in which AB=AC.

Construct AP bisector of angle A meeting BC at P.

In ∆ABP and ∆ACP

AP=AP[common]

AB=AC[given]

angle BAP=angle CAP[by construction]

Therefore, ∆ABP congurent ∆ACP[S.A.S]

This implies, angle ABP=angleACP[C.P.C.T]

8 0
3 years ago
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