Answer:
GREATER than 1 g/cm. 3, it will SINK in water. LESS than 1 g/cm3, it will FLOAT in water. If an object's density is: Density of Object > Density of Liquid.
Explanation:
To solve the problem, use Kepler's 3rd law :
T² = 4π²r³ / GM
Solved for r :
r = [GMT² / 4π²]⅓
but first covert 6.00 years to seconds :
6.00years = 6.00years(365days/year)(24.0hours/day)(6...
= 1.89 x 10^8s
The radius of the orbit then is :
r = [(6.67 x 10^-11N∙m²/kg²)(1.99 x 10^30kg)(1.89 x 10^8s)² / 4π²]⅓
= 6.23 x 10^11m
Answer:
1.718 N , attractive
Explanation:
r = 0.66 m, n = 5.7 x 10^13
q1 = 5.7 x 10^13 x 1.6 x 10^-19 = 9.12 x 10^-6 C
q2 = - 5.7 x 10^13 x 1.6 x 10^-19 = - 9.12 x 10^-6 C
F = K q1 q2 / r^2
F = 9 x 10^9 x 9.12 x 10^-6 x 9.12 x 10^-6 / (0.66)^2
F = 1.718 N
As both the charges are opposite in nature, so the force between them is attractive.
An atom gains one or more electrons and becomes negatively charged, or loses one or more electrons and becomes positively charged.
