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FromTheMoon [43]
3 years ago
5

Suppose you go outside and look at three stars. Star A is blue, star B is white, and star C is red. Which star is the hottest, a

nd which star is the coldest?
(Figure 4)

a. Star A is the hottest, and star C is the coldest.
b. Star B is the hottest, and star C is the coldest.
c. Star A is the hottest, and star B is the coldest.
Physics
2 answers:
N76 [4]3 years ago
8 0

Answer:irs a

Explanation:

Trava [24]3 years ago
5 0

Answer:

Order the following stars from coolest to hottest.

star A, star B, star C

star B, star C, star A

<em><u>star B, star A, star C </u></em>

star C, star B, star A

Explanation:

The bolded is the answer.

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Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The
bazaltina [42]

Answer:

The current in the rods is 171.26 A.

Explanation:

Given that,

Length of rod = 0.85 m

Mass of rod = 0.073 kg

Distance d = 8.2\times10^{-3}\ m

The rods carry the same current in the same direction.

We need to calculate the current

I is the current  through each of the wires then the force per unit length on each of them is

Using formula of force

\dfrac{F}{L}=\dfrac{\mu_{0}I^2}{2\pi d}

\dfrac{mg}{L}=\dfrac{\mu_{0}I^2}{2\pi d}

Where, m = mass of rod

l = length of rod

Put the value into the formula

I^2=\dfrac{mgd}{\mu L}

I^2=\dfrac{0.073\times9.8\times8.2\times10^{-3}}{2\times10^{-7}}

I=\sqrt{29331.4}

I=171.26\ A

Hence, The current in the rods is 171.26 A.

5 0
3 years ago
The electron affinity of thulium has been measured by a technique known as laser photodetachment electron spectroscopy. In this
antoniya [11.8K]

Answer:

ΔE = 1.031 eV

Explanation:

For this exercise let's calculate the energy of the photons using Planck's equation

          E = h f

wavelength and frequency are related

         c = λ f

         f = c /λ

let's substitute

         E = h c /λ

let's calculate

         E = 6.63 10⁻³⁴ 3 10⁸/1064 10⁻⁹

         E = 1.869 10⁻¹⁹ J

let's reduce to eV

         E = 1.869 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)

        E = 1.168 eV

therefore the electron affinity is

         ΔE = E - 0.137

         ΔE = 1.168 - 0.137

         ΔE = 1.031 eV

3 0
3 years ago
The velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in
pochemuha

Since g is constant,  the force the escaping gas exerts on the rocket will be 10.4 N

<h3>What is Escape Velocity ?</h3>

This is the minimum velocity required for an object to just escape the gravitational influence of an astronomical body.

Given that the velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in 0.60s. The gravitational field intensity is 9.8N/kg.

To calculate the force the escaping gas exerts of the rocket, let first highlight all the given parameters

  • Mass (m) of the rocket 0.25 Kg
  • Initial velocity u = 15 m/s
  • Final Velocity v = 40 m/s
  • Time t = 0.6s
  • Gravitational field intensity g = 9.8N/kg

The force the gas exerts of the rocket = The force on the rocket

The rate change in momentum of the rocket = force applied

F = ma

F = m(v - u)/t

F = 0.25 x (40 - 15)/0.6

F = 0.25 x 41.667

F = 10.42 N

Since g is constant,  the force the escaping gas exerts on the rocket is therefore 10.4 N approximately.

Learn more about Escape Velocity here: brainly.com/question/13726115

#SPJ1

7 0
2 years ago
I need help on US history portfolio but before you help me...
alex41 [277]

Answer:

1. They believed the British were treating the colonists unfairly.

2. The British passed many tax laws that impacted the colonists.

3. The King of England wanted to tax the Colonists without giving them representation in British parliament.

4. The Colonists decided they wanted a better and stronger government, one that would listen to them.

6 0
3 years ago
Express 50,000 m/s2 in scientific notation.
Volgvan
5x10 to the 4th power
8 0
3 years ago
Read 2 more answers
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