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FromTheMoon [43]
3 years ago
14

A gas is contained in a thick-walled balloon. When the pressure changes from 45.0 bar to 96.0 bar, the volume changes from 1.20

L to ____ L and the temperature changes from 314 K to 420 K.
What decimal or number goes in the blank?
Chemistry
2 answers:
icang [17]3 years ago
8 0

Answer:

The final volume of the gas is 0.752 L.

Explanation:

Initial pressure of the gas =P_1=45.0 bar

Initial volume of the gas =V_1=1.20L

Initial temperature of the gas =T_1=314 K

Final pressure of the gas =P_2=96.0 bar

Final volume of the gas =V_2=?

Final temperature of the gas =T_2=420 K

Number of moles of gases are constant

Using an ideal gas equation :

PV=nRT

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

V_2=\frac{45.0 bar\times 1.20 L\times 420 K}{314 K\times 96 bar}=0.752 L

The final volume of the gas is 0.752 L.

notsponge [240]3 years ago
5 0

P1 * V1 ÷ T1 = P2 * V2 ÷ T2  

45 * 1.20 ÷ 314 = 96 * V2 ÷ 420  

30,144 * V2 = 22,680  

V2 = 22,680 ÷ 30,144  

The new volume is approximately 0.75 liter.

I hope I helped

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Fe(s) + CuSO4(aq) ⇒ Cu(s) + FeSO4(aq)
Alexxandr [17]

Answer:

The answer to your question is CuSO₄

Explanation:

To answer your question just remember the following information

- A chemical reaction is divided into sections

 reactants and products

 reactants on the left side of the reaction

products on the right side of the reaction

- All the symbols have a meaning

 (s) means that that compound is in solid phase

 (aq) means that that compound is dissolved in solution.

Then, the answer is CuSO₄

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3 years ago
Why is it that 85.48 rounded to two significant figures is 85 and not 86?
Gelneren [198K]

Answer:

See below.

Explanation:

That is because  of the .48.

85.48 is closer to 85 than 86.

8 0
3 years ago
Part III.The two reactions involved in quantitatively determining the amount of iodate in solution are: IO3-(aq) 5 I-(aq) 6 H (a
slega [8]

Answer:

\large \boxed{\math{\dfrac{\text{6 mol thiosulfate}}{\text{1 mol iodate}}}}

Explanation:

The I₂ is the common substance in the two equations.

(1) IO₃⁻ + 5I⁻ + 6H⁺ ⟶ 3I₂ + 3H₂O

{2) I₂ + 2S₂O₃²⁻ ⟶ 2I⁻ + S₄O₆²⁻

From Equation (1), the molar ratio of iodate to iodine is

\dfrac{\text{I}_{2}}{\text{IO}_{3}^{-}} = \dfrac{3}{1}

From Equation (2), the molar ratio of iodine to thiosulfate is

\dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{I}_{2}} = \dfrac{2}{1}

Combining the two ratios, we get

\text{Stoichiometric factor} = \dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{IO}_{3}^{-}} = \dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{I}_{2}} \times \dfrac{\text{I}_{2}}{\text{IO}_{3}^{-}} = \dfrac{2}{1} \times \dfrac{3}{1} = \mathbf{\dfrac{6}{1}}\\\\\text{The stoichiometric factor is $\large \boxed{\mathbf{\dfrac{\text{6 mol thiosulfate}}{\text{1 mol iodate}}}}$}

7 0
3 years ago
A sample of phosphonitrilic bromide, PNBr2, contains 2.01 mol of the compound. Determine the amount (in mol) of each element pre
nordsb [41]

Answer:

2.01 moles of P → 1.21×10²⁴ atoms

2.01 moles of N → 1.21×10²⁴ atoms

4.02 moles of Br → 2.42×10²⁴ atoms

Explanation:

We begin from this relation:

1 mol of PNBr₂ has 1 mol of P, 1 mol of N and 2 moles of Br

Then 2.01 moles of PNBr₂ will have:

2.01 moles of P

2.01 moles of N

4.02 moles of Br

To determine the number of atoms, we use the relation:

1 mol has NA (6.02×10²³) atoms

Then: 2.01 moles of P will have (2.01  . NA) = 1.21×10²⁴ atoms

2.01 moles of N (2.01  . NA) = 1.21×10²⁴ atoms

4.02 moles of Br (4.02 . NA) = 2.42×10²⁴ atoms

6 0
3 years ago
Read 2 more answers
What are the compounds empirical and molecular formulas
Liono4ka [1.6K]

Answer:

The empirical formula is the simplest ratio of atoms while molecular is the actual formula.

Explanation:

Empirical Formula is the simplest ratio of atoms present in the compound.

The molecular formula shows the actual number of atoms present in the compound.

For example, CH is the empirical formula and C6H6 is the molecular formula of benzene.

5 0
2 years ago
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