In a closed container with a fixed volume, when the temperature of a gas doubles, the pressure of the gas is?

A primary amine contains a five-membered carbon ring. The degree of unsaturation for the five-membered carbon ring is equal to t

IceJOKER [234]

Answer:

C₇H₁₁N

Explanation:

To find the chemical formula, first, let's evaluate the given conditions.

1. Is a primary amine:

This means that the amine is connected to a carbon, like NH₂-R

2. The degree of unsaturation of the five-membered carbon ring is equal to three:

One of the degrees of unsaturation is for the five-membered carbon ring, the other two are for pi-bonds. This means that the five-membered carbon ring has 2 pi-bonds inside.

3. There are seven carbon atoms:

Five of these seven carbons are for the carbon ring and the other two are bonded to the primary amine.

From all of the above, we have that the chemical formula is:

C₅H₅-C₂H₄-NH₂ = C₇H₁₁N

I hope it helps you!

7 0

2 years ago

What is the approximate ratio of [NO2-] to [HNO2] in order to buffer a solution at pH=4.0?

Strike441 [17]

For the equilibrium that exists in an aqueous solution of nitrous acid (HNO2, a weak acid) ... [H+][NO2. –]. [HNO2]. PAGE: 14.1. 2. Which of the following is a conjugate ... Using the following Ka values, indicate the correct order of base strength. HNO2. Ka = 4.0 × 10–4 .... Calculate the [H+] in a solutionthat has a pH of 11.70.
i hope thid works

6 0

3 years ago

Citrate synthase catalyzes the reaction: ????x????????o????c???????????????????? + ????c????????y???? − ????o???? → c???????????

Nady [450]

The given question is incomplete. The complete question is as follows.

Citrate synthase catalyzes the reaction

Oxaloacetate + acetyl-CoA $\rightarrow$ citrate + HS-CoA

The standard free energy change for the reaction is -31.5 kJ*mol^-1

( a) Calculate the equilibrium constant for this reaction a 37degrees C

Explanation:

(a). It is known that , relation between change in free energy ( $\Delta G$ ) of a reaction and equilibrium constant (K) is as follows.

$\Delta G = -RT \times ln K$

where, T = temperature in Kelvin

The given data is as follows.

T = 310 K, $\Delta G = -31.5 kJ /mol = -31500 J/mol$ (as 1 kJ = 1000 J)

Now, putting the given values into the above formula as follows.

ln K = $\frac{-(\Delta G)}{RT}$

= $\frac{31500}{8.314 \times 310}$

ln K = 12.22

K = antilog (12.22)

= $2.1 \times 10^{5}$

Therefore, we can conclude that value of equilibrium constant for the given reaction is $2.1 \times 10^{5}$ .

6 0

3 years ago

(CH3)2-CH-CH2-O(CH3)3IUPAC NAME

bazaltina [42]

Answer:

1-(tert-butoxy)-2-methylpropane

Note: there is a mistake in formula, the correct formula is (CH₃)₂-CH-CH₂-O-C(CH₃)₃ not (CH₃)₂-CH-CH₂-O(CH₃)₃, because oxygen is a divalent compound.

Explanation:

Structural formula is attached

IUPAC naming rules

1. start numbering the chain from the functional group. In this compound we start from oxygen side.

2. Here we can see that at position 1 there is an oxy group along with a tertiary carbon having three methyl groups. So we write it as 1-tert-butoxy. Which means that there is a methoxy group at position 1 along with a tertiary carbon.

3. At position 2 we can see that there is a methyl group attached to the main chain, so we write it as 2-methyl.

4. Now we count the total number of carbons in the main chain. As we can see that there are 3 carbons in the remaining or parent chain, so we write it as propane

5. So the IUPAC name of the compound will be 1-(tert-butoxy)-2-methylpropane

3 0

3 years ago

Which pair of elements would you expect to exhibit the greatest similarity in their physical and chemical properties? Sr, Te Ga,

Anvisha [2.4K]

Answer:

Explanation:

N and P will have similarity

Electronic configuration of N

2,5

1s²2s²p⁵

Electronic configuration of P

1s²2s²2p⁶3s²3p⁵

Electronic configuration bears similarity.

Both have 5 electrons in their outermost orbits . So they exhibit similarity in their properties. Both belong to the same 15 th group of periodic table.

Sr and Rb too bear much similarity . Both are strongly electro-positive metal , difference in their atomic no being only one.

5 0

3 years ago