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3 years ago

A reaction occurs when one compound reacts and is broken down into different elements or simpler compounds.

Chemistry

2 answers:

dangina [55]3 years ago

8 0

Answer:

decomposition on edg

Explanation:

Inessa [10]3 years ago

3 0

Answer:

Decomposition Reaction

Explanation:

If you are referring to what type of reaction that occurred then the answer would be decomposition reaction.

This is a chemical reaction where one reactant is broken down into two or more products.

REACTANT → PRODUCT

AB → A + B

The products can be two or more elements or two or more compounds, depending on what was decomposed.

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I need help I know it isnt A

inna [77]

It is B. Thank you later please and do good on the test!

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3 years ago

Read 2 more answers

If the lab technician needs 30 liters of a 25% acid solution, how many liters of the 10% and the 30% acid solutions should she m

Mice21 [21]

Answer:

7.5 L of the 10% and 22.5 L of the 30% acid solution, she should mix.

Explanation:

Let the volume of 10% acid solution used to make the mixture = x L

So, the volume of 30% acid solution used to make the mixture = y L

Total volume of the mixture = x + y = 30 L .................. (1)

For 10% acid solution:

C₁ = 10% , V₁ = x L

For 30% acid solution :

C₂ = 30% , V₂ = y L

For the resultant solution of sulfuric acid:

C₃ = 25% , V₃ = 30 L

Using

C₁V₁ + C₂V₂ = C₃V₃

10×x + 30×y = 25×30

So,

x + 3y = 75 .................. (2)

Solving 1 and 2 we get,

x = 7.5 L

y = 22.5 L

6 0

3 years ago

Why is it important for someone to hold enzymes in their functional shapes

kumpel [21]

Answer:

there are spaces within the enzymes that is active. That active site allows substrates to join in. This helps the enzyme carry out the chemical reaction with the substrate.

Explanation:

4 0

3 years ago

Formula unit of Magnesium oxide and Calcium bicarbonate and aluminum carbonate plzzzz

Fudgin [204]

Magnesium oxide : MgO

Calcium bicarbonate: Ca(HCO3)2

aluminum carbonate: Al2(CO3)3 or C3Al2O9

5 0

3 years ago

Silver occurs in trace amounts in some ores of lead, and lead can displace silver from solution: Pb(s) + 2Ag+ (aq) LaTeX: \longr

VikaD [51]

Answer : The value of $\Delta G^o$ and K is, -180 kJ/mol and $3.6\times 10^{31}$

Explanation :

The balanced cell reaction will be,

$Pb(s)+2Ag^+(aq)\rightarrow Pb^{2+}(aq)+2Ag(g)$

The half-cell reactions are:

Oxidation reaction (anode) : $Pb(s)\rightarrow Pb^{2+}(aq)+2e^-$

Reduction reaction (cathode) : $2Ag^+(aq)+2e^-\rightarrow 2Ag(g)$

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_{cell}$

where,

$\Delta G^o$ = standard Gibbs free energy

F = Faraday constant = 96500 C

n = number of electrons in oxidation-reduction reaction = 2

$E^o_{cell}$ = standard electrode potential of the cell = 0.93 V

Now put all the given values in the above formula, we get:

$\Delta G^o=-2\times 96500\times 0.93$

$\Delta G^o=-179490J/mol=-179.49kJ/mol\approx -180kJ/mol$

Now we have to calculate the value of 'K'.

$\Delta G^o=-RT\ln K$

where,

$\Delta G_^o$ = standard Gibbs free energy = -180 kJ/mol

R = gas constant = $8.314\times 10^{-3}kJ/mole.K$

T = temperature = 298 K

K = equilibrium constant = ?

Now put all the given values in the above formula 1, we get:

$-180kJ/mol=-(8.314\times 10^{-3}kJ/mole.K)\times (298K)\times \ln K$

$K=3.6\times 10^{31}$

Therefore, the value of $\Delta G^o$ and K is, -180 kJ/mol and $3.6\times 10^{31}$

5 0

3 years ago