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aleksklad [387]
3 years ago
15

how to write a conversion factor that relates moles of HCL to moles of NiCO3 to the reaction of hydrochloric acid reacts with so

me reacts with solid nickel carbonate
Chemistry
1 answer:
Lelu [443]3 years ago
5 0

Answer:

See below.

Step-by-step explanation:

We call this conversion factor the <em>molar ratio.</em>

1. Start with the <em>balanced equation </em>

NiCO₃ + 2HCl ⟶ NiCl₂ + H₂O + CO₂

2. Note the <em>coefficients</em> of the substances

The equation tells you that 1 mol of NiCO₃ reacts with 2 mol of HCl·

Thus, the conversion factor is either (1 mol NiCO₃/2 mol HCl) or (2 mol HCl/1 mol NiCO₃).

You choose the one that gives the correct units for the answer.

<em>For example</em>, if the question was, "How many moles of HCl will react with x mol of NiCO₃," you would write

x mol NiCO₃ × (2 mol HCl/1 mol NiCO₃) ⟶ 2x mol HCl

Notice that putting "mol HCl" in the numerator and "mol NiCO₃" in the denominator cancels "mol NiCO₃" and gives you the desired units of "mol HCl" in the answer .

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276 grams of carbon in 23.0 moles
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anyanavicka [17]
The density is 3 because the density remains the same.
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What type of molecule is butanoic acid?
ira [324]

Answer:

option b.

Explanation:

<em>Carboxylic acid</em>

3 0
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Read 2 more answers
Select all the correct answers.
Andrei [34K]

Scientists use scientific notation to communicate extremely small measurements. Hence, option A is correct.

<h3>What scientific notation?</h3>

Scientific notation is a way of writing very large or very small numbers.

Scientists use scientific notation to represent very small or very large numbers because this notation increases the  

  • accuracy of measured quantities.

  • convenience in using the numbers.

  • the number of significant figures.

  • precision of measurements.

Hence, option A is correct.

Learn more about the scientific notation here:

brainly.com/question/18073768

#SPJ1

4 0
2 years ago
Use the data given below to construct a Born-Haber cycle to determine the heat of formation of KCl. Δ H°(kJ) K(s) → K(g) 89 K(g)
AURORKA [14]

Explanation:

The net equation will be as follows.

          K(s) + Cl_{2}(g) \rightarrow KCl(s)

So, we are required to find \Delta H_{formation} for this reaction.

Therefore, steps involved for the above process are as follows.

Step 1:  Convert K from solid state to gaseous state

          K(s) \rightarrow K(g),    \Delta H_{1} = 89 kJ

Step 2:  Ionization of gaseous K

           K(g) \rightarrow K^{+}(g) + e^{-},    H_{2} = 418 KJ

Step 3:  Dissociation of Cl_{2} gas into chlorine atom .

            \frac{1}{2} Cl_{2}(g) \rightarrow Cl(g),   \Delta H_{3} = \frac{244}{2} = 122 KJ

Step 4: Iozination of chlorine atom.

              Cl(g) + e^{-} \rightarro Cl^{-}(g),      H_{4} = -349 KJ

Step 5:  Add K^{+} ion and Cl^{-} ion formed above to get KCl .

              K^{+}(g) + Cl^{-}(g) \rightarrow KCl(s),   H_{5} = -717 KJ

Now, using Born-Haber cycle, value of enthalpy of the formation is calculated as follows.

      \Delta H_{f} = \DeltaH_{1} + \Delta H_{2} + \Delta H_{3} + \Delta H_{4} + \Delta H_{5}

                  = 89 + 418 + 122 - 349 - 717

                  = - 437 KJ/mol

Thus, we can conclude that the heat of formation of KCl is - 437 KJ/mol.

5 0
3 years ago
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