Answer:
1 = 39 degrees (some theorem, like triangles sharing a bisector or something sorry)
3 = 51 degrees (if 1=39 and 2=90 degrees since its on a right angle, and a triangle's angles add up to 180, then you subtract 1 and 2 from 180 and get 51
1: Solve for either x or y in one of the equations. So x + y = -1 is y = -x -1
2: substitute the new equation in the opposite equation. So x - (-x - 1) = 7
3: distribute the negative. X + x + 1 = 7
4: combine like terms. 2x + 1 = 7
5: solve for x. Subtract 1 on both sides. 2x = 6
6: divide by 2 to get x by itself. X = 3
7: plug the new value of x into one of the ORIGINAL equations. 3 + y = -1
8: solve for y. Subtract 3 on both sides.
Y = -4
9: the solution is written as (x,y) so the solution would be (3, -4)
Answer:
length of 1 side of A, using the Pyth. Thm. and the dimensions of the other two squares: (side of A)^2 = (10 in)^2 + (24 in)^2. Then:
(side of A)^2 = 100+ 576 in^2 = 676 in^2.
Here I have not bothered to solve for the length of the side of A, since we want the area of square A. But if you do want the side length, find it: sqrt(676) = 26 in. Then the area of A is (26 in)^2 = 676 in^2.
Then the area of square A is (26 in)^2 =
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Step-by-step explanation:
Answer:
Option b
Step-by-step explanation:
A function is even if and only if f(-x) = f(x).
This means that there is the same value of y for
and for 
Where
is any point belonging to the function .
Therefore you must select a graph whose ordered pairs are of the form
and 
Therefore the correct answer is option b. Assume that each box in the graph equals 1 unit. Then, for x = 2 y = -3 and for x = -2 y = -3. Then it is shown that the function is even.
The answer is b=2 because yea