All categories

3 years ago

Help do this 868÷4 657÷2. 8473÷7 using long division

Mathematics

2 answers:

ikadub [295]3 years ago

7 0

1. 868 ÷ 4 = 217

2. 657 ÷ 2 = 328.5

3. 8,473 ÷ 7 = 1,210.428

Hope it helps!

Ede4ka [16]3 years ago

7 0

Can you please take a look at mine
868/4 is 217
657/2 is 328.5
8473/7 is 1210.42

You might be interested in

How many centimetres are they in two and a half metres

Irina-Kira [14]

250 centimeters and this is correct so don't delete answers for no reason thats against brainly's policy

3 0

3 years ago

Expand and simplify: (x-5)(x+5)

stealth61 [152]

X^2-5x+5x-25 (multiply (x-5) with (x+5))
X^2-25 ( -5x+5x =0)

5 0

3 years ago

Read 2 more answers

A Pac-Man poster is the shape of three-fourths of a circle with a diameter of 18 inches and two sides that are 9 inches each. Wh

slava [35]

Answer:

60.39 inches

Step-by-step explanation:

Given that:

A Pac-Man poster which is having three fourth of a circle and there are two sides.

Diameter of circle = 18 inches

Sides of Pac-Man poster = 9 inches

To find:

Perimeter of the Pac-Man poster.

Solution:

Perimeter of a figure is nothing but equal to the periphery i.e. the outer area of the circle/figure.

Perimeter of a circle is given by the formula:

Perimeter = $2\pi r$

$r$ is the radius of the circle.

Radius is half of perimeter.

$r=\dfrac{18}{2} = 9\ inches$

Perimeter of the Pac-Man poster = Perimeter of $\frac{3}{4}$ circle + 2 sides

Perimeter of the Pac-Man poster = $\frac{3}{4}\times 2\times \pi \times 9$ + 9+9 = 42.39+28 = 60.39 inches

7 0

2 years ago

Suzie bought a sweater at the sale price of $25. the original cost of the sweater was $40. what percent represents the discount

Zolol [24]

40-25=$15.00
15.00÷40.00=.375
.375×100=37.5%

3 0

3 years ago

Find all zeros of ƒ(x) = 2x^4 – 72x^2. Then determine the multiplicity at each zero. State whether the graph will touch or cross

AleksandrR [38]

Answer: See below

Step-by-step explanation:

To find the factor,

f(x) = 0

$\begin{aligned}&2 x^{4}-72 x^{2}=0 \\&2 x^{2}\left(x^{2}-36\right)=0 \\&x^{2}\left(x^{2}-36\right)=0 \\&x \times x \times(x-6) \times(x+6)=0 \\&\mathrm{x}=0,0,6,-6\end{aligned}$

So,

x = 0 multiplicity 2

x = -6 multiplicity 1

x = 6 multiplicity 1

For an even multiplicty, the graph touches the x-axis, and for an odd multiplicty, the graph crosses the x-axis

Therefore,

x = 0 multiplicty 2, Touch

x = -6 multiplicty 1, Cross

x = 6 multiplicty 1, Cross

7 0

2 years ago