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MrMuchimi
3 years ago
5

What is the net cell reaction for the cobalt-silver voltaic cell? express your answer as a chemical equation?

Chemistry
1 answer:
slava [35]3 years ago
6 0

Answer: The net ionic equation for the cobalt-silver voltaic cell is Co(s)+3Ag^+(aq.)\rightarrow Co^{3+}(aq.)+3Ag(s)

Explanation: In cobalt-silver voltaic cell, one half of the cell consists of cobalt electrode immersed in Co(NO_3)_3 solution ( which means that Co^{3+} are present in the solution) and other half of the cell consists of the Ag electrode immersed in AgNO_3 solution ( which means that Ag^+ is present in the solution)

The two electrodes are joined by the copper wire. The cobalt electrode acts as an anode and the silver electrode acts a  cathode.

At anode, oxidation reaction takes place and at cathode, reduction reaction takes place.

At Anode :                    Co(s)\rightarrow Co^{3+}(aq.)+3e^-

At Cathode:                   [Ag^+(aq.)+e^-\rightarrow Ag(s)]\times 3

Net ionic equation:   Co(s)+3Ag^+(aq.)\rightarrow Co^{3+}(aq.)+3Ag(s)

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The reaction for producing glucose in plants, called photosynthesis, is:
Firlakuza [10]

Answer:

41.16 moles of H2O

Explanation:

Ratio for the products-reactants is 1:6, so 1 mol of glucose is produced when plants use 6 moles of water.

Then, let's make a rule of three:

1 mol of glucose is produce by using 6 moles of water

6.86 moles of glucose are produced by the use of (6 . 6.86)/1 = 41.16 moles of H2O

8 0
4 years ago
A block of pine wood has a mass of 120 g and a volume of 300 cm3. What is the density of wood? (Show your work)
Zielflug [23.3K]

Answer:

The answer is

<h2>0.4 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}

From the question

mass of wood = 120 g

volume = 300 cm³

So the density of the wood is

density =  \frac{120}{300}  \\  =  \frac{12}{30}  =  \frac{2}{5}

We have the final answer as

<h3>0.4 g/cm³</h3>

Hope this helps you

5 0
3 years ago
Write the name of the compounds
blagie [28]

P2O5 = Phosphorus pentoxide

CuO = Copper (II) oxide

NH4CI = Ammonium Chloride

Mn(OH)2 = Pyrochroite

H2O2 = Hydrogen peroxide

P4S9 = Tetraphosphorus nonasulfide

CIO2 = Chlorine dioxide  

NaF = Sodium fluoride

FeSO3 = Iron (II) Sulfite

Fe(NO3)3 = Iron (III) Nitrate  

Cr(NO2)3 = Chromium (III) Nitrite

NaHCO3 = Sodium Hydrogen Carbonate  

H2PO4 = Dihydrogen Phosphate Ion  

NaCN = Sodium Cyanide  

IF7 = Iodine Heptafluoride  

PCI3 = Phosphorus Trichloride

5 0
3 years ago
What would be the effect on the nucleus of an atom if it emitted one alpha particle and one gamma ray
Oksana_A [137]
Unstable, radioactive atom emits alpha and gamma ray to transform into a stable atom.

Emitting an alpha particle, decreases the mass number by four and atomic number by two.
Emitting gamma ray reduces the excess energy of the radioactive atom.
4 0
3 years ago
Suppose the half-life is 9.0 s for a first order reaction and the reactant concentration is 0.0741 M 50.7 s after the reaction s
bazaltina [42]

<u>Answer:</u> The time taken by the reaction is 84.5 seconds

<u>Explanation:</u>

The equation used to calculate half life for first order kinetics:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half-life of the reaction = 9.0 s

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{9}=0.077s^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}     ......(1)

where,

k = rate constant  = 0.077s^{-1}

t = time taken for decay process = 50.7 sec

[A_o] = initial amount of the reactant = ?

[A] = amount left after decay process =  0.0741 M

Putting values in equation 1, we get:

0.077=\frac{2.303}{50.7}\log\frac{[A_o]}{0.0741}

[A_o]=3.67M

Now, calculating the time taken by using equation 1:

[A]=0.0055M

k=0.077s^{-1}

[A_o]=3.67M

Putting values in equation 1, we get:

0.077=\frac{2.303}{t}\log\frac{3.67}{0.0055}\\\\t=84.5s

Hence, the time taken by the reaction is 84.5 seconds

6 0
3 years ago
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