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MrMuchimi
2 years ago
5

What is the net cell reaction for the cobalt-silver voltaic cell? express your answer as a chemical equation?

Chemistry
1 answer:
slava [35]2 years ago
6 0

Answer: The net ionic equation for the cobalt-silver voltaic cell is Co(s)+3Ag^+(aq.)\rightarrow Co^{3+}(aq.)+3Ag(s)

Explanation: In cobalt-silver voltaic cell, one half of the cell consists of cobalt electrode immersed in Co(NO_3)_3 solution ( which means that Co^{3+} are present in the solution) and other half of the cell consists of the Ag electrode immersed in AgNO_3 solution ( which means that Ag^+ is present in the solution)

The two electrodes are joined by the copper wire. The cobalt electrode acts as an anode and the silver electrode acts a  cathode.

At anode, oxidation reaction takes place and at cathode, reduction reaction takes place.

At Anode :                    Co(s)\rightarrow Co^{3+}(aq.)+3e^-

At Cathode:                   [Ag^+(aq.)+e^-\rightarrow Ag(s)]\times 3

Net ionic equation:   Co(s)+3Ag^+(aq.)\rightarrow Co^{3+}(aq.)+3Ag(s)

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First, we need to get moles of NaOH:

when moles NaOH = volume * molarity 

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from the reaction equation:

H3PO4(aq) + 3NaOH → 3 H2O(l) + Na3PO4(aq)

we can see that when 1 mol H3PO4 reacts with→ 3 mol NaOH

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∴ moles H3PO4 = 0.0028 mol / 3 = 9.4 x 10^-4 mol

now we can get the concentration of H3PO4:

∴[H3PO4] = moles H2PO4 / volume

               = 9.4 x 10^-4 / 0.034 L

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