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MrMuchimi
3 years ago
5

What is the net cell reaction for the cobalt-silver voltaic cell? express your answer as a chemical equation?

Chemistry
1 answer:
slava [35]3 years ago
6 0

Answer: The net ionic equation for the cobalt-silver voltaic cell is Co(s)+3Ag^+(aq.)\rightarrow Co^{3+}(aq.)+3Ag(s)

Explanation: In cobalt-silver voltaic cell, one half of the cell consists of cobalt electrode immersed in Co(NO_3)_3 solution ( which means that Co^{3+} are present in the solution) and other half of the cell consists of the Ag electrode immersed in AgNO_3 solution ( which means that Ag^+ is present in the solution)

The two electrodes are joined by the copper wire. The cobalt electrode acts as an anode and the silver electrode acts a  cathode.

At anode, oxidation reaction takes place and at cathode, reduction reaction takes place.

At Anode :                    Co(s)\rightarrow Co^{3+}(aq.)+3e^-

At Cathode:                   [Ag^+(aq.)+e^-\rightarrow Ag(s)]\times 3

Net ionic equation:   Co(s)+3Ag^+(aq.)\rightarrow Co^{3+}(aq.)+3Ag(s)

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Which is a common unbalanced force acting on objects in motion?
Semmy [17]

Answer:

a. friction

Explanation:

What is a common unbalanced force acting in motion? Common forces that are often unbalanced include the force of gravity and applied forces. When these forces are unbalanced, objects accelerate, change their position and find new configurations for which all forces are again balanced.

Friction is a kind of force.

5 0
3 years ago
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Which pair of elements would most likely combine to form a salt? I and F Cs and I Na and C N and F
Savatey [412]

Answer:

Cs and I

Explanation:

Salts are formed when an ionic bond is formed between two elements in the compound. Let us recall that the kind of bond formed between any two elements depends on the magnitude of electronegativity difference between the two elements.

Among the options listed, the highest degree of electronegativity difference occurs for the bond between Cs and I. This implies that this bond is ionic and the combination of the two elements will lead to salt formation.

7 0
3 years ago
As student used a pen to draw a line across a piece of chromatography paper. he then placed a sample of dye on the drawn line fo
AleksAgata [21]

Answer is in the photo. I can only upload it to a file hosting service. link below!

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3 0
3 years ago
Calculate the equilibrium constant k for the isomerization of glucose-1-phosphate to fructose-6-phosphate at 298 k. express your
k0ka [10]
We cannot solve this problem without using empirical data. These reactions have already been experimented by scientists. The standard Gibb's free energy, ΔG°, (occurring in standard temperature of 298 Kelvin) are already reported in various literature. These are the known ΔG° for the appropriate reactions.

<span>glucose-1-phosphate⟶glucose-6-phosphate          ΔG∘=−7.28 kJ/mol
fructose-6-phosphate⟶glucose-6-phosphate          ΔG∘=−1.67 kJ/mol
</span>
Therefore, the reaction is a two-step process wherein glucose-6-phosphate is the intermediate product.

glucose-1-phosphate⟶glucose-6-phosphate⟶fructose-6-phosphate 

In this case, you simply add the ΔG°. However, since we need the reverse of the second reaction to end up with the terminal product, fructose-6-phosphate, you'll have to take the opposite sign of ΔG°.

ΔG°,total = −7.28 kJ/mol  + 1.67 kJ/mol = -5.61 kJ/mol

Then, the equation to relate ΔG° to the equilibrium constant K is

ΔG° = -RTlnK, where R is the gas constant equal to 0.008317 kJ/mol-K.
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lnK = 2.2635
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6 0
3 years ago
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An archaeologist graduate student found a leg bone of a large animal during the building of a new science building. The bone had
Vlad [161]

Answer : The time passed in years is 2.74\times 10^2\text{ years}

Explanation :

Half-life of carbon-14 = 5730 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{5730\text{ years}}

k=1.21\times 10^{-4}\text{ years}^{-1}

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 1.21\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = ?

a = initial amount of the reactant disintegrate = 15.3

a - x = amount left after decay process = 14.8

Now put all the given values in above equation, we get

t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{15.3}{14.8}

t=274.64\text{ years}=2.74\times 10^2\text{ years}

Therefore, the time passed in years is 2.74\times 10^2\text{ years}

4 0
4 years ago
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