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Salsk061 [2.6K]
3 years ago
8

Identify the type of reaction in KBrO3(s)  KBr(s) + O2(g)

Chemistry
2 answers:
lord [1]3 years ago
5 0
<span>I believe an oxidation reaction is occurring</span>
Taya2010 [7]3 years ago
4 0
I had this question in chemistry, and i'm sure it's a <span> decomposition reaction.</span>
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What is the mass of 3.35 mol Hg(IO3)2? 1,700 g 1,840 g 1,960 g 2,110 g
vichka [17]

Answer:- 1840 g.

Solution:- We have been given with 3.35 moles of  and asked to calculate it's mass.

To convert the moles to grams we multiply the moles by the molar mass of the compound. Molar mass of the compound is the sum of atomic masses of all the atoms present in it.

molar mass of  = atomic mass of Hg + 2(atomic mass of I) + 6(atomic mass of O)

= 200.59+2(126.90)+6(16.00)

= 200.59+253.80+96.00

= 550.39 gram per mol

Let's multiply the given moles by the molar mass:

3.35mol(\frac{550.39g}{1mol})

= 1843.8 g

Since, there are three sig figs in the given moles of compound, we need to round the calculated my to three sig figs also. So, on rounding off to three sig figs the mass becomes 1840 g.



5 0
3 years ago
Which of these items best describes the arrangement of electrons in an atom of sulfur? A. Eight electrons in its first energy le
Serga [27]

D. Two electrons in its first energy level; eight electrons in its second energy level; six valence electrons in its outermost energy level.

Please correct me if I'm wrong!! :)


6 0
3 years ago
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Calculate the mass of 2.50 mol of methanol.
solmaris [256]

Answer:

60g

Explanation:

Moles = mass / mollar mass

Mass = Moles x mollar mass

Mass = 2.50 x 24

Mass = 60g

7 0
3 years ago
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An iron bar of mass 841 g cools from 84°C to 7°C. Calculate the heat released (in kilojoules) by the metal.
Oduvanchick [21]

Answer:

28.75211 kj

Explanation:

Given data:

Mass of iron bar = 841 g

Initial temperature = 84°C

Final temperature = 7°C

Heat released = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

specific heat capacity of iron is 0.444 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 7°C - 84°C

ΔT = -77°C

By putting values,

Q = 841 g × 0.444 j/g.°C × -77°C

Q = 28752.11 j

In Kj:

28752.11 j × 1 kJ / 1000 J

28.75211 kj

8 0
3 years ago
Which situation is an example of heat transfer by radiation?
Artist 52 [7]
Answer is:
The sun's energy is transferred through the vacuum of space to Earth
5 0
3 years ago
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