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I am Lyosha [343]
3 years ago
14

The nth term of a sequence is 25-3n

Mathematics
2 answers:
jeyben [28]3 years ago
7 0
A)
T¹=25-3(1)=22
T²=25-3(2)=19
T³=25-3(3)=16

b)
t^ {10}  = 25 - 3(10)  =  - 5

Komok [63]3 years ago
5 0

Answer:

22, 19, 16 and - 5

Step-by-step explanation:

To evaluate any term from the n th term formula substitute the terms position value for n

given a_{n} = 25 - 3n, then

(a)

a_{1} = 25 - (3 × 1) = 25 - 3 = 22

a_{2} = 25 - (3 × 2) = 25 - 6 = 19

a_{3} = 25 - (3 × 3) = 25 - 9 = 16

(b)

a_{10} = 25 - (3 × 10) = 25 - 30 = - 5


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3 years ago
What type of solution is x^2 + 10x + 25 = 0
MaRussiya [10]
Hello.

There is only one solutin for <span> x^2 + 10x + 25 = 0

You can tell because it ends with a 0.

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5 0
3 years ago
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A dentist polls his patients and finds that 83 percent brush their teeth at least twice a day, 47 percent floss daily, and 19 pe
puteri [66]

Answer:

The correct option is B. 23%

Step-by-step explanation:

Let the event that patient brushes his teeth at least twice a day is denoted by A

So, P(A) = 0.83

Let the event that patient flosses daily is denoted by B

So, P(B) = 0.47

Now, it is given that 19 percent patients brush at least twice a day and floss daily.

⇒ P(A and B) = 0.19

Now, we need to find conditional probability of occurring event B given A has occurred.

\implies P(B|A) =\frac{P(A\: and\: B)}{P(A)}\\\\\implies P(B|A) = \frac{0.19}{0.83}\\\\\implies P(B|A) = 0.2289\approx 0.23

Hence, Nearest required percentage = 23%

Therefore, The correct option is B. 23%

4 0
3 years ago
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SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP
nata0808 [166]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

Step-by-step explanation:

Given the system of the equations

x+3y=5;\:x=-6y+14

solving by elimination method

\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}

\mathrm{Arrange\:equation\:variables\:for\:elimination}

\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}

x+6y=14

-

\underline{x+3y=5}

3y=9

\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}

solve 3y=9 for y:

3y=9

\frac{3y}{3}=\frac{9}{3}

y=3

\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3

Solve x+3\cdot \:3=5 for x:

x+3\cdot \:3=5

x+9=5

x=-4

Therefore,

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

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3 years ago
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Xelga [282]
Carlene needs to sell 480 shirts to meet her goal.
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3 years ago
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