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Black_prince [1.1K]
3 years ago
5

PLEASE HELP!

Mathematics
1 answer:
Orlov [11]3 years ago
3 0
We have that
<span>If (5x-4+13x=5) -------------->  then x=1/2
Step 1
</span>let's substitute the value of x = (1/2) in the expression [5x-4+13x] and verify its result
5*(1/2)-4+13*(1/2)
(5/2)-4+(13/2)
(5-4*2+13)/2----------> (5-8+13)/2=10/2=5
then 
5=5-----------> <span>the value of x = (1/2) satisfies equality</span>


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A standard number cube will be painted on each side that has an even number. The length of one side of the cube is 10 mm. What i
BaLLatris [955]

Answer:

300 mm^2

Step-by-step explanation:

1st: Find the surface area of one side

10 mm x 10 mm = 100 mm^2

2nd: Multiply the surface area of one side by the amount of sides that are even

100 mm x 3 sides = 300 mm^2

5 0
3 years ago
Seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Find the probability that (a)
UNO [17]

Answer:

a) P=0.226

b) P=0.6

c) P=0.0008

d) P=0.74

Step-by-step explanation:

We know that the seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Therefore, we have 46 balls.

a) We calculate the probability that are 3 red, 2 blue, and 2 green balls.

We calculate the number of possible combinations:

C_7^{46}=\frac{46!}{7!(46-7)!}=53524680

We calculate the number of favorable combinations:

C_3^{12}\cdot C_2^{16}\cdot C_2^{18}=660\cdot 120\cdot 153=12117600

Therefore, the probability is

P=\frac{12117600}{53524680}\\\\P=0.226

b) We calculate the probability that are at least 2 red balls.

We calculate the probability  withdrawn of 1 or none of the red balls.

We calculate the number of possible combinations:

C_7^{46}=\frac{46!}{7!(46-7)!}=53524680

We calculate the number of favorable combinations: for 1 red balls

C_1^{12}\cdot C_7^{34}=12\cdot 1344904=16138848

Therefore, the probability is

P_1=\frac{16138848}{53524680}\\\\P_1=0.3

We calculate the number of favorable combinations: for none red balls

C_7^{34}=5379616

Therefore, the probability is

P_0=\frac{5379616}{53524680}\\\\P_0=0.1

Therefore, the  the probability that are at least 2 red balls is

P=1-P_1-P_0\\\\P=1-0.3-0.1\\\\P=0.6

c) We calculate the probability that are all withdrawn balls are the same color.

We calculate the number of possible combinations:

C_7^{46}=\frac{46!}{7!(46-7)!}=53524680

We calculate the number of favorable combinations:

C_7^{12}+C_7^{16}+C_7^{18}=792+11440+31824=44056

Therefore, the probability is

P=\frac{44056}{53524680}\\\\P=0.0008

d) We calculate the probability that are either exactly 3 red balls or exactly 3 blue balls are withdrawn.

Let X, event that exactly 3 red balls selected.

P(X)=\frac{C_3^{12}\cdot C_4^{34}}{53524680}=0.57\\

Let Y, event that exactly 3 blue balls selected.

P(Y)=\frac{C_3^{16}\cdot C_4^{30}}{53524680}=0.29\\

We have

P(X\cap Y)=\frac{18\cdot C_3^{12} C_3^{16}}{53524680}=0.12

Therefore, we get

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\\\P(X\cup Y)=0.57+0.29-0.12\\\\P(X\cup Y)=0.74

8 0
3 years ago
Robin has 10 books. Thère is enough space on a shelf for 4 books. In how many ways can 4 of the 10 books bearranged on the shelf
sveticcg [70]

If the 10 books are all different, we have:

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,

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• 8 ways of selecting the third book,

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• 7 ways of selecting the fourth book.

The total number of ways to arrange 4 of the 10 books is:

10\cdot9\cdot8\cdot7=5040.

Answer

There are 5040 ways of arranging the books.

7 0
1 year ago
The minute hand of a clock turns 6° per minute. In fifteen minutes the
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Answer:

25%

Step-by-step explanation:

15 times 6 is 90

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8 0
3 years ago
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Hi I need help on my math the mid-chapter checkpoint
masya89 [10]

Answer:

do you know how to divide without a calculator? you should really learn...but here 3=211,4=60.875,5=410.25,6=307.23

8 0
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