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Amiraneli [1.4K]
3 years ago
6

Please use Python 3 to solve the following problem. Please also show all outputs and share code.The variable sentence stores a s

tring. Write code to determine how many words in sentence start and end with the same letter, including one-letter words. Store the result in the variable same_letter_count.Hard-coded answers will receive no credit.sentence = "students flock to the arb for a variety of outdoor activities such as jogging and picnicking"
Computers and Technology
1 answer:
Harman [31]3 years ago
5 0

Answer:

The code is given in Python below with its output.

Explanation:

"""

User is asked to enter the input in sentence

"""

sentence=input("Enter the sentence :")

"""

sentence is converted to list named words

"""

words=sentence.split()

same_letter_count=0

"""

In for loop we access each word

and check character at index 0 and at last index

is same or not.

"""

for word in words:

 if word[0] == word[len(word)-1]:

   same_letter_count+=1

 

print("The same letter count is",same_letter_count)

<u>OUTPUT:: </u>

TEST CASE 1::

Enter the sentence :students flock to the arb for a variety ofoutdoor activities such as jogging and picknicking

The same letter count is 2

TEST CASE 2::

Enter the sentence :i am a bit madam

The same letter count is 3

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write a C program the prints out the size of variables with the following C data types- int, long, unsigned, long long, double,
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<u>C program for finding size of different data types</u>

#include <stdio.h>

//driver function

int main()

{

   int a;  //declaring a of type int

   float b; //declaring b of type float

   double c; //declaring c of type double

   char d; //declaring d of type char

   long e; //declaring e of type long

   long long f; //declaring f of type longlong

   unsigned g; //declaring g of type unsigned

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printf("char data type contains: %lu byte\n",sizeof(d));/*Finding size of char */

printf("long data type contains: %lu byte\n",sizeof(e));/*Finding size of long*/ printf("longlong data type contains: %lu byte\n",sizeof(f));/*Finding size of longlong */

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   return 0;

}

<u>Output</u>

int data type contains: 4 bytes

float data type contains : 4 bytes

double data type contains: 8 bytes

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long data type contains: 8 byte

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Answer:

   while(userNum>=1){

       System.out.print(userNum/2+" ");

       userNum--;

        }

Explanation:

This is implemented in Java programming language. Below is a complete code which prompts a user for the number, receives and stores this number in the variable userNum.

<em>import java.util.Scanner;</em>

<em>public class TestClock {</em>

<em>    public static void main(String[] args) {</em>

<em>    Scanner in = new Scanner (System.in);</em>

<em>        System.out.println("Enter the number");</em>

<em>    int userNum = in.nextInt();</em>

<em>    while(userNum>=1){</em>

<em>        System.out.print(userNum/2+" ");</em>

<em>        userNum--;</em>

<em>         }</em>

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Answer:

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