Which function has an inverse that is not a function?
1 answer:
Answer:
your choice is correct
Step-by-step explanation:
f(x) = x^2 does not pass the horizontal line test (a horizontal line intersects its graph in two places), so its inverse does not pass the vertical line test. The inverse is not a function.
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Comment on the graph
The original function f(x)=x^2 is shown by the red curve. Its reflection across the orange dashed line y=x gives the inverse relation, in blue. The black horizontal and vertical lines show the multiple points of intersection with the curves, indicating the inverse relation is not a function.
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Start with the answer format we want, and work your way toward forming a single fraction like so
Compare that last expression to (2x+1)/(x+2). Notice how the ax and 2x match up, so a = 2 must be the case.
Then we have 2a+b as the remaining portion in the numerator. Plugging in a = 2 leads to 2a+b = 2*2+b = 4+b. Set this equal to the +1 found in (2x+1)/(x+2) to have the terms match.
So, 4+b = 1 leads to b = -3
Therefore, a = 2 and b = -3
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An alternative route:
I added and subtracted 4 in the third step so that I could form 2x+4, which then factors to 2(x+2). That way I could cancel out a pair of (x+2) terms toward the very end.
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Other alternative methods involve synthetic division or polynomial long division. They are slightly separate but related concepts.