Answer:
B.(-1,2)
Step-by-step explanation:
In a function, there can not be two different values of y corresponding to the same value of x.
See the graph attached.
Here, the points on the graph are (1,2), (2,-3), (-2,-2) and (-3,1).
If we consider point (-2,2) then there will be two points corresponding to the same x value i.e. (-2,-2) and (-2,2).
Similarly, if we consider the point (2,-2) or (2.-1) then also there becomes more than one values of y for a single value of x i.e. x = 2.
So, if we consider the ordered pair (-1,2) then only the graph still represents a function. (Answer)
We know that it costs $68 for 16 square feet of flooring. To find out how much it costs for 12, we first have to find out how much it costs for 1 square foot.
To find that, we would do $68 divided by 16, which is 4.25.
That means 1 square foot costs $4.25.
Then, we would multiply $4.25 by 12 to find how much 12 square feet costs.
$4.25 times 12 is 51.
So, it would cost $51 to have 12 square feet of flooring.
when y = -11, 0 + y is equal to -11.
the question is asking us to add 0 to the given value of y. the given value of y is -11, so place -11 into 0 + y and you get 0 + -11. since you are adding zero, you are making no changes to the y value, so it stays at -11.
<em>hope this helps and have a great day!</em>
Answer:
6/63
Step-by-step explanation:
To find the probability in fraction form you must first add all the evidence together and then use that number as the denominator
Answer:
a.
.
b. 
Step-by-step explanation:
By the definition, the expected value of a random variable X with probability mass function p is given by
where the sum runs over all the posible values of X. Given a function g, the random variable Y=g(X) is defined. Note that the function g induces a probability mass function P' given by P'(Y=k) = P(X=g^{-1}(k)) when the function g is bijective.
a. Note that for 1/3ln(2)+1/6ln(5) by choosing the function g(x) = ln(x) the expression coincides with E(g(x)), because if Y = g(x) then E(Y) = P'(Y=1)*ln(1)+P'(Y=2)*ln(2)+P'(Y=5)*ln(5) = P(X=1)*ln(1)+P(X=2)*ln(2)+P(X=5)*ln(5).
b. On the same fashion, the function g(x) = xe^{xt} fullfills the expression of E[g(X)]